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svet-max [94.6K]
3 years ago
14

Assume that it is equally likely for a child to be born a boy or a girl, and that the Lin family is planning on having three chi

ldren. List the elements of the event that the Lins have at least one girl. (Use B to represent boy, and G to represent girl. For example, if there are three girls born, it would be represented as GGG).
Mathematics
1 answer:
nevsk [136]3 years ago
6 0

Answer:

List = \{GBB; BGB; BBG; GGB; BGG; GBG; GGG\}

Step-by-step explanation:

Given

Children = 3

Required

List all cases of having at least 1 girl

We have:

B = Boy

G = Girl

For 1 girl, we have:

GBB; BGB; BBG

For 2 girls, we have:

GGB; BGG; GBG

For 3 girls, we have:

GGG

Hence, the list is:

List = \{GBB; BGB; BBG; GGB; BGG; GBG; GGG\}

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Answer:

150 games won: 110 games lost

Step-by-step explanation:

Ratios

150:110

150/110

150 to 110

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Robin's scores: 99, 108, 102, 107, 119
VashaNatasha [74]
<h3>The medians does'nt support the conclusion</h3>

<em><u>Solution:</u></em>

Given that,

Robin's scores: 99, 108, 102, 107, 119

Order the number from least to greatest

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Median is the middle value of data set

Median is 107

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Order the number from least to greatest

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The median of Evelyn's scores is greater than the median of Robin's

Therefore, the medians does'nt support the conclusion.

4 0
4 years ago
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Please help with this question!
alexira [117]
A=107
B=107
C=73

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