Work out radius of 1.43 x 10^5

Alice searches for her term paper in her filing cabinet, which has several drawers. She knows thatshe left her term paper in dra

katen-ka-za [31]

You made a mistake with the probability $p_{j}$ , which should be $p_{i}$ in the last expression, so to be clear I will state the expression again.

So we want to solve the following:

Conditioned on this event, show that the probability that her paper is in drawer $j$ , is given by:

(1) $\frac{p_{j} }{1-d_{i}p_{i} } , if j \neq i,$ and

(2) $\frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} } , if j = i.$

so we can say:

$A$ is the event that you search drawer $i$ and find nothing,

$B$ is the event that you search drawer $i$ and find the paper,

$C_{k}$ is the event that the paper is in drawer $k, k = 1, ..., n.$

this gives us:

$P(B) = P(B \cap C_{i} ) = P(C_{i})P(B | C_{i} ) = d_{i} p_{i}$

$P(A) = 1 - P(B) = 1 - d_{i} p_{i}$

Solution to Part (1):

if $j \neq i$ , then $P(A \cap C_{j} ) = P(C_{j} )$ ,

this means that

$P(C_{j} |A) = \frac{P(A \cap C_{j})}{P(A)} = \frac{P(C_{j} )}{P(A)} = \frac{p_{j} }{1-d_{i}p_{i} }$

as needed so part one is solved.

Solution to Part(2):

so we have now that if $j$ = $i$ , we get that:

$P(C_{j}|A ) = \frac{P(A \cap C_{j})}{P(A)}$

remember that:

$P(A|C_{j} ) = \frac{P(A \cap C_{j})}{P(C_{j})}$

this implies that:

$P(A \cap C_{j}) = P(C_{j}) \cdot P(A|C_{j}) = p_{i} (1-d_{i} )$

so we just need to combine the above relations to get:

$P(C_{j}|A) = \frac{p_{i} (1-d_{i} )}{1-d_{i}p_{i} }$

as needed so part two is solved.

8 0

3 years ago

Divide: 5/11 •2/5 HURRY PLEASE

Kamila [148]

Answer:

0.1818

Step-by-step explanation:

0.4545 x 0.4

3 0

3 years ago

Read 2 more answers

Which best describe the relationship between the two lines describe below?

Anna007 [38]

we have

6x+3y=12 -----> line p

Find the slope

3y=-6x+12

y=-2x+4

m=-2

-4x=2y-2 -----> line Q

2y=-4x+2

y=-2x+1

m=-2

therefore

the lines are parallel because their slopes are equal

7 0

1 year ago

Show All Work

Angelina_Jolie [31]

The unit rate you're trying to find is pages per day(or p/d), so the equation needs to have both a unit for pages and for days.
The equation we have is:
$5,249 = 29d$
If they read 5,249 pages, then we can include the unit for pages in the equation.
Since we also know that d is the number of days it took, you can replace d with days.
The equation becomes:
$5,249\ pages=29*(x\days)$
Now that we have one variable, we can solve for p/d:
$\frac{5,249\ pages}{29}=x\ days\\\\181 = x$
Thus it took them 181 days to read it all.

If Johnny read 5,249 pages over 181 days and the unit rate is pages per day(p/d), then the equation for finding p/d is:
$\frac{p\ pages}{d\ days}=\frac{5,249\ pages}{181\ days}=\frac{29\ pages}{1\ day}\\\\29\ \frac{pages}{day}$
Johnny read 29 pages per day.

8 0

3 years ago

4x-3y=-29, 4x-3y=-30

Nat2105 [25]

Answer:

Is this slope or do you want me to solve x and y

Step-by-step explanation:

4 0

2 years ago