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2 years ago

What is the equivalent expression of . (1/4)x - (1/2)

Mathematics

1 answer:

luda_lava [24]2 years ago

5 0

Answer:

1/4x + (-1/2) hope this helped!

Step-by-step explanation:

You might be interested in

Rewrite in simplest radical form square root of x times the fourth root of x. Show each step of your process.

Ipatiy [6.2K]

Answer:

$\sqrt[4] {x^3}$

Step-by-step explanation:

At this point, we can transform the square root into a fourth root by squaring the argument, and bring into the other root:

$\sqrt x \cdot \sqrt[4] x =\sqrt [4] {x^2} \cdot \sqrt[4] x = \sqrt[4]{x^2\cdot x} = \sqrt[4] {x^3}$

Alternatively, if you're allowed to use rational exponents, we can convert everything:

$\sqrt x \cdot \sqrt[4] x = x^{\frac12} \cdot x^\frac14 = x^{\frac12 +\frac14}= x^{\frac24 +\frac14}= x^\frac34 = \sqrt[4] {x^3}$

5 0

1 year ago

What is the value of the expression below when w=3?<br><br><br>6w-9

Nikitich [7]

Answer:

Step-by-step explanation:

Substitute w = 3 into the expression

6w - 9

= 6(3) - 9

= 18 - 9

= 9

6 0

2 years ago

Can someone please help me on this?

ki77a [65]

Going down the chart:
6
4
3
4
6

the brackets on the outside of the lxl makes the value positive or keeps the value positive. therefor if u have y=l-3l+3 y will still =6! hope this helps!

6 0

2 years ago

Tamara and Amir shared a candy bar. Tamara ate two fifths. Amir ate two fifths. How much is left?

marin [14]

Answer:

1/5

Step-by-step explanation:

Both Amir and Tamara ate 2/5 each.

2/5 + 2/5 = 4/5

If 4/5 of the candy bar was eaten, 1/5 of the candy bar remains because

5/5 - 4/5 = 1/5

(Remember that 5/5 just equals one whole, representing the whole candy bar)

7 0

2 years ago

Lizzie has 30 coins that total $4.80. All of her coins are dimes, D, and quarters, Q. Algebraically determine how many of each t

Gnom [1K]

Lizzie has 18 dimes and 12 quarters

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

$d \times 0.10 + q \times 0.25 = 4.80$

0.1d + 0.25q = 4.8 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

0.15q = 1.8

From eqn 3,

d = 30 - 12

Thus she has 18 dimes and 12 quarters

6 0

2 years ago