The answer is 114.5%.
Let the original population be denoted by x.
Now, let's go through the percentage increase per year.
<u>Year 1</u>
<u>Year 2</u>
- 1.2x (1 + 25%)
- 1.2x (1.25)
- 1.5x
<u>Year 3</u>
- 1.5x (1 + 30%)
- 1.5x (1.3)
- 1.95x
<u>Year 4</u>
- 1.95x (1 + 10%)
- 1.95x (1.1)
- 2.145x
Overall increase : 214.5% - 100% = 114.5%
Hence, the overall percentage increase in these 4 years is 114.5%.
(1) let "r" denote number of rabbits, "c" number of chickens
Set up the equations:
Answer: There are 575 rabbits and 425 chickens
(2) m - number of Mike's stamps, a - number of Andrew's stamps.
Set up equations:
Answer: Mike has 48 stamps. Andrew has 12 stamps.
36+10=46
=46
(20 characterssss)
Hi,
New temperature will be 31 F - 15 F = 16 F.
Green eyes.
Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
