For the case of a line through
(
2
,
7
)
and
(
1
,
−
4
)
we have
slope
m
=
Δ
y
Δ
x
=
−
4
−
7
1
−
2
=
−
11
−
1
=
11
Using the point
(
2
,
7
)
we can write the equation of the line in point slope form as:
y
−
7
=
m
(
x
−
2
)
where the slope
m
=
11
.
That is:
y
−
7
=
11
(
x
−
2
)
To get point intercept form, first expand the right hand side so...
y
−
7
=
11
x
−
(
11
⋅
2
)
=
11
x
−
22
Then add
7
to both sides to get:
y
=
11
x
−
15
=
11
x
+
(
−
15
)
This is point intercept (
y
=
m
x
+
c
) form with slope
m
=
11
and intercept
c
=
−
15
.
Answer:
Sometimes
Step-by-step explanation:
I’ll give you an example so you can understand:
Let’s say x is 4. So plug 4 into the problem:
|4|=4 → This is a very true statement, where the absolute value of 4 is equal to 4.
Now, let’s say x is -7. So plug -7 into the problem:
|-7|=-7 → This is a false statement because it’s saying that the absolute value of -7 is -7 which is very untrue.
So |x|=x only works for positive numbers, but not negative numbers. Therefore, |x|=x is the absolute value of x <u>sometimes.</u>
<u />
Hope this helps and answers your question! :)
Answer:
1/6
Step-by-step explanation:
A six sided die has 6 options, you can roll a 1,2,3,4,5,6. You cannot "remove" numbers and with a single die, you can't roll anymore than one number at a time. 2 is one option out of 6, therefore your answer is 1/6.
Answer:
x=2
y=-3
Step-by-step explanation:
9514 1404 393
Answer:
(-2, 2)
Step-by-step explanation:
The orthocenter is the intersection of the altitudes. The altitude lines are not difficult to find here. Each is a line through the vertex that is perpendicular to the opposite side.
Side XZ is horizontal, so the altitude to that side is the vertical line through Y. The x-coordinate of Y is -2, so that altitude has equation ...
x = -2
__
Side YZ has a rise/run of -1/1 = -1, so the altitude to that side will be the line through X with a slope of -1/(-1) = 1. In point-slope form, the equation is ...
y -(-1) +(1)(x -(-5))
y = x +4 . . . . . . . . subtract 1 and simplify
The orthocenter is the point that satisfies both these equations. Using the first equation to substitute for x in the second, we have ...
y = (-2) +4 = 2
The orthocenter is (x, y) = (-2, 2).
