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3 years ago

Please Help!!! What two numbers go there?

Mathematics

1 answer:

marshall27 [118]3 years ago

6 0

The answer is 9/7!! Hope it helps

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Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie

melamori03 [73]

Answer:

The complete solution is

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

$y = e^{mx}$

Differentiating with respect to x

$y'= me^{mx}$

Again differentiating with respect to x

$y''= m ^2 e^{mx}$

Putting the value of y, y' and y'' in left side of the differential equation

$3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0$

$\Rightarrow 3m^2-8m-3=0$

The auxiliary equation is

$3m^2-8m-3=0$

$\Rightarrow 3m^2 -9m+m-3m=0$

$\Rightarrow 3m(m-3)+1(m-3)=0$

$\Rightarrow (3m+1)(m-3)=0$

$\Rightarrow m = 3, -\frac13$

The complementary function is

$y= Ae^{3x}+Be^{-\frac13 x}$

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)

For particular integral

$y_p=\frac 1{(3D+1)(D-3)} .4$

$=4.\frac 1{(3D+1)(D-3)} .e^{0.x}$ [since $e^{0.x}=1$ ]

$=4\frac{1}{(3.0+1)(0-3)}$ [ replace D by 0 , since L(0)≠0]

$=-\frac43$

The complete solution is

y= C.F+P.I

$\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43$

4 0

3 years ago

If a piece of cardboard is 6 in long and I line up a hundred and ten of them what would be the length of my row and feet

Alex

6in x 110 = 660in = 55ft

8 0

3 years ago

2×-y when ×= when 5 and y=12

Damm [24]

25-12=13 because if x=5 and y=12 just replace the letters with the numbers. Hope it helps mate

6 0

3 years ago

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Rewrite using a single positive exponent.<br> 78<br> 73

vivado [14]

Hey! I don’t know if this is what you mean.. but I tried to understand it.

78^1
73^1

Have a good day :)

3 0

2 years ago

PLZ HURRY! WILL GIVE BRAINELST! WORTH 100

Anit [1.1K]

Answer:

Could you screen-clip the question? I can't really understand.

Step-by-step explanation:

You can edit your question and I can edit my answer :)

~PumpkinSpice1

4 0

2 years ago

Read 2 more answers