Let c= cost to rent each other
Let t= cost to rent each other
2c+3t=25
6T+5T=49
Multiply the 2nd equation by (-2) and add equation together
2c+3t=25
-12c-10t= 98
2t=98
T=49
Put this value into the 1st equation solve c
2c+3(49)=49
2c+147=49
2c=98
C=49
Cost to each chair and table are same 49.
Answer:
left to right
yes no no no yes yes yes yes yes yes yes no
Step-by-step explanation:
the x values can only have 1 y
Y's can have as many X's
We need the figure to answer that.
The answer is B.
I hope this helps. :)
Answer:
x= 3
Step-by-step explanation:
