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2 years ago

ASAP I NEED HELP ON NO. 1

Mathematics

1 answer:

Furkat [3]2 years ago

4 0

Answer:

Step-by-step explanation:

The other ones are false claims

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2 years ago

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Prove that the difference between a two-digit number and the product of its digits will always be a 2 digit number.

slamgirl [31]

Step-by-step explanation:

Let the two-digit number is $xy$

This can be written as:

10x + y, where 1 ≤ x ≤ 9 and 0 ≤ y ≤ 9

The difference between the number and product of its digits is:

d = 10x + y - xy

Rewrite this as below:

d = 10x - xy + y - 10 + 10 =

x(10 - y) - (10 - y) + 10 =

(x - 1)(10 - y) + 10

We see that:

0 ≤ x - 1 ≤ 8 according to the condition given above
1 ≤ 10 - y ≤ 10 again according to the condition given above

The value of d is then:

0 + 10 ≤ d ≤ 8*10 + 10
10 ≤ d ≤ 90

<h3>Proved</h3>

7 0

2 years ago

Read 2 more answers

What is the equivalent ratio of 26:7

anastassius [24]

Answer:

52 : 14

Step-by-step explanation:

multiply the numbers by 2

3 0

2 years ago

the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

nikdorinn [45]

$l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}$
$length\approx9.71cm;\ width\approx17.71cm$

4 0

3 years ago

GEOMETRY HELP PLZ

tangare [24]

Answer:

0.324

0.068

Step-by-step explanation:

If Russell is 5'9" ; then he is under 6 feets :

Probability = number of forwards under 6 feets / tot number of players

Probability = 120 / 370 = 0.324

Peter is 6'2" ; Peter is over 6 feets ;

Probability that Peter is a guard = (number of guards over 6 feets / total number of players) = 25 / 370 = 0.0676 = 0.068

8 0

2 years ago