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3 years ago

Write an equation for the following situation: A student reads 65 pages per hour.

1 answer:

8 0

Answer: 65h
Explanation: if the student read 65 pages per house you would multiply the hours read by 65 to determine the number of pages read :)

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If f(x) = -4x + 2 and g(x) = sq root X – 8,<br>what is (fºg)(12)?

Anettt [7]

Answer:

$(fog)(12)=-6$

Step-by-step explanation:

Recall that the notation: $(fog)(12)$ is the same as: $f(g(12))$ which means the value of the function f when you give it as input the value obtained by evaluating g(12).

Therefore, we need to start finding what g(12) is using the definition :

$g(x)=\sqrt{x-8}$ and evaluating it as x = 12.

$g(x)=\sqrt{x-8}\\g(12)=\sqrt{12-8}\\g(12)=\sqrt{4}\\g(12)=2$

So now we use this answer "2" as input for f(x):

$f(x)=-4x+2\\f(2)=-4(2)+2\\f(2)=-8+2\\f(2)=-6$

Therefore, $(fog)(12)=-6$

3 0

4 years ago

2 fraction that is equal to 1/4

prisoha [69]

<span>that would be my dear 2/8, 3/12,</span>

3 0

3 years ago

Read 2 more answers

Need to find the answer to 10 times (-2 ) -8

tekilochka [14]

10 × -2 is -20
-20 -8 = -28

5 0

4 years ago

Read 2 more answers

Given h(x) = -5x + 3, find h(5).

lyudmila [28]

5x+5=3
5x=-2
X=-2/5
Alternative form is x=-0.4

6 0

3 years ago

A glass paperweight has a composite shape: a square pyramid fitting exacty on top of an 8 centimeter cube. The pyramid has a hei

ArbitrLikvidat [17]

Answer:

Part 1) The volume of the paperweight is $576\ cm^{3}$

Part 2) The total surface area of the paperweight is $400\ cm^{2}$

Step-by-step explanation:

Part 1) what is the volume of the paperweight?

we know that

The volume of the paperweight is equal to the volume of the square pyramid plus the volume of the cube

step 1

Find the volume of the pyramid

The volume of the pyramid is equal to

$V=\frac{1}{3}BH$

where

B is the area of the square base

H is the height of the pyramid

$B=8^{2}=64\ cm^{2}$

$H=3\ cm$

substitute

$V=\frac{1}{3}(64)(3)=64\ cm^{3}$

step 2

Find the volume of the cube

The volume of the cube is equal to

$V=b^{3}$

$V=8^{3}=512\ cm^{3}$

step 3

Find the volume of the paperweight

$64\ cm^{3}+512\ cm^{3}=576\ cm^{3}$

Part 2) what is the total surface area of the paperweight?

we know that

The total surface area of the paperweight is equal to the surface area of 5 faces of the cube plus the lateral area of the pyramid

step 1

Find the surface area of 5 faces of the cube

$SA=5b^{2}$

$SA=5(8^{2})=320\ cm^{2}$

step 2

Find the lateral area of the pyramid

$LA=4[\frac{1}{2}bh]$

$LA=4[\frac{1}{2}(8)(5)]=80\ cm^{2}$

step 3

Find the total surface area of the paperweight

$320\ cm^{2}+80\ cm^{2}=400\ cm^{2}$

8 0

3 years ago