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Margarita [4]
2 years ago
11

Tina is saving to buy a notebook computer. She has two options. The first option is to put $400 away initially and save $20 ever

y month. The second option is to put $100 away initially and save $40 every month. After how many months would Tina save the same amount using either option? How much would she save with either option?
Mathematics
2 answers:
dolphi86 [110]2 years ago
7 0

Answer:

The first option is to put $400 away initially and save $20 every month. Let she saves for x months. Equation becomes;

400+20x

The second option is to put $100 away initially and save $40 every month.  Let she saves for x months. Equation becomes;

100+40x

Equating both as equal we will get the number of months.

400+20x=100+40x

=> 40x-20x=400-100

=> 20x=300

x = 15

Hence, it will take 15 months to save the same amount.

And amount saved will be = 400+20(15)

= $700

fenix001 [56]2 years ago
5 0
1st month: $100 + 40 = 140 | 400 + 20 = 420
2nd month: 180 | 440
3rd month: 220 | 460
4th month: 260 | 480
5th month: 300 | 500
After five months, the distance between the amount of money saved has decreased by $100. 5 x 3 = 15, therefore the amount of money saved will be the same after 15 months. 

Hope this helps!

Ash
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RideAnS [48]

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For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/

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In other words - eight tenths plus one ninth = forty-one forty-fifths.

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