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Debora [2.8K]
3 years ago
5

Need to get this one right to pass lesson

Mathematics
2 answers:
Gnesinka [82]3 years ago
6 0

Answer:

not sure search it up

Step-by-step explanation:

Cerrena [4.2K]3 years ago
4 0

Answer:

33ft²

Step-by-step explanation:

b= base (3)

l= slant height (4)

Surface area = b²+2bl

=3²+2(3)(4)

=9+2(12)

=33

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Please help!! ASAP!!
kotegsom [21]

Answer:

26. t<-70 see description below.

Step-by-step explanation:

To solve an inequality in one variable, solve using inverse operations like any other equations. However, if dividing or multiplying by a negative at any points, flip the sign of the inequality.


Example:

\frac{t}{-7}>10\\\\ -7*\frac{t}{-7} >10*-7\\\\t

-7 was multiplied to as an inverse operation to division by -7. Because it was negative, the inequality sign was flipped. To graph, plot -70 on the number line with an open circle. Then draw an arrow from -70 to the left.

8 0
3 years ago
Is 0.09 more or less than 0.9? same with 0.06 and 0.6.
In-s [12.5K]
.09 is less than 0.9.
8 0
3 years ago
Read 2 more answers
Which number is rational?
ziro4ka [17]

Answer:

We need some numbers to work with to truly answer this. However here's a definition of a rational numbers

A rational number is any number that isn't infinite and non-repeating. So decimals, fractions, repeating numbers/decimals like 1.535353.... (53 is the "pattern") are all rational and fair game. Numbers like pi (π), "imperfect" square roots, etc. that don't repeat and are infinite or NOT RATIONAL.

<u>Hope this helps and have a nice day!</u>

<u />

5 0
3 years ago
In 8 years tamika will be 22 how old is she now?
aleksandrvk [35]

Answer:

14

Step-by-step explanation:

22-8=14

6 0
3 years ago
Read 2 more answers
Simplify x+2/x^2+2x-3 divide by x+2/x^2-x
ira [324]

\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}

If x\neq-2, then we can immediately cancel the factors of x+2:

\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}

Factorize the numerator and denominator:

x^2-x=x(x-1)

x^2+2x-3=(x+3)(x-1)

Next, if x\neq1, then

\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}

8 0
3 years ago
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