2 years ago

R/19 > -1 please help solve for R

Mathematics

1 answer:

pantera1 [17]2 years ago

8 0

Answer:

Step-by-step explanation:

$\frac{r}{19}>-1$

Multiply both sides by 19

$\frac{r}{19}*19>-1*19 \\\\r > -19$

You might be interested in

Simplify each of the following expressions.

Veronika [31]

Here you go :) have a good day

3 0

2 years ago

Read 2 more answers

Least to the greatest number of 103,718 and 121,356 and 113,635

muminat

103,718 113,635 121,356

7 0

2 years ago

Read 2 more answers

2. Which is the BEST definition of a line's x-intercept?

asambeis [7]

Answer:

Step-by-step explanation:

balls in yo jaws

5 0

2 years ago

Whats the answer and steps to 5g+4(-5+3g)=1-g

Lady_Fox [76]

$5g+4(-5+3g)=1-g \\\\ 5g-20+12g=1-g \\\\ 17g-20=1-g\\\\ 17g+g=1+20\\\\18g=21 \\\\ \boxed{g=\frac{21}{18}=\frac{7}{6}}$

4 0

3 years ago

Read 2 more answers

2.<br> Which of the functions below is an inverse of the quadratic function f(x) = x2 - 3 ?

mezya [45]

Answer:

the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

Step-by-step explanation:

We need to find inverse of the quadratic function $f(x) = x^2 - 3$

Let

$y=x^2-3$

Replace x and y

$x=y^2-3$

Now, we will solve for y

Adding 3 on both sides

$x+3=y^2-3+3$

$x+3=y^2$

Taking square root on both sides

$\sqrt{y^2}=\sqrt{x+3}\\y=\pm \sqrt{x+3}$

Now replace y with $f^{-1}(x)$

$f^{-1}(x)=\pm \sqrt{x+3}$

So, the inverse of the quadratic function $f(x) = x^2 - 3$ is $\mathbf{f^{-1}(x)=\pm \sqrt{x+3}}$

3 0

2 years ago