Let A(1,13) and B (6,11) be two points. Find the slop of the line which passes through M(5,8) and is perpendicular to the line A
B
1 answer:
Answer: 5/2
Step-by-step explanation:
First, we need to find the slope of AB. To do that, I will use the equation
y2 - y1/x2 - x1
Plug in the coordinates.
11 - 13/6 - 1
Simplify.
-2/5
<u>Our slope for line AB is -2/5</u>. Now we can find the slope that is perpendicular to it that passes through the point (5, 8).
To do that, just take the slope from AB and make it an opposite value and reciprocal.
Our slope is 5/2.
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32 + (5 − 2) ⋅ 4 − 6 over 3
=32 + 3 ⋅ 4 − 6/3
=32 + 12− 2
=44 - 2
= 42
÷
Multiply
by the reciprocal of
, which is
=
×
=
We can simplify it further:
The greatest common factor here is
168
=
Answer:
1,3
Step-by-step explanation:
=(x^2-1)(x^2-9)=0
x=1,x=3
Its 6.0 i think im sory is wrong
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