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melamori03 [73]
3 years ago
14

PLEASE HELP! 20 PTS

Mathematics
1 answer:
blagie [28]3 years ago
7 0

Answer: The answers are B, C, and D (I took the quiz and it was right)

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Which is a rule that describes the translation of a point from 4, -8 to 7, -10
Alexxandr [17]

Answer:

\large\boxed{(x,\ y)\to (x+3,\ y-2)}

Step-by-step explanation:

(4,\ -8)\to(7,\ -10)\\\\4\to7\Rightarrow4+3=7\\\\-8\to-10\Rightarrow-8-2=-10\\\\\text{Conclusion}\\\\(x,\ y)\to (x+3,\ y-2)

4 0
3 years ago
Read 2 more answers
Find the distance between the points.<br> (r, s) and (0, 0)
zhenek [66]

Answer:  \sqrt{r^2+s^2

=====================================================

Reason:

Plot the points (0,0) and (r,s). You can place (r,s) anywhere you want.

Connect the two points mentioned and form a right triangle such that the segment from (0,0) to (r,s) is the hypotenuse of said right triangle.

The horizontal leg has a length of r-0 = r units, while the vertical leg will be 's' units.

Check out the diagram below.

We then apply the pythagorean theorem to say r^2+s^2 = h^2 where h is the hypotenuse. Solving for h gets us h = \sqrt{r^2+s^2}. We only focus on the positive square root since a negative hypotenuse makes no sense.

Since we made the hypotenuse the segment with endpoints (r,s) and (0,0), this means the hypotenuse length and the distance are the same thing.

Therefore, the distance from (r,s) to (0,0) is \sqrt{r^2+s^2}

As an alternative, you can use the distance formula to get the same answer. The distance formula is effectively the pythagorean theorem phrased a different way.

5 0
2 years ago
What is the LCM of 2, 4, and 5?
marta [7]

Answer:

20

Step-by-step explanation:

the LCM of 2, 4, and 5?

2

{2}^{2}  \times 5

7 0
3 years ago
7
Sergio [31]

Answer:

Ummmmmmmm me no know

Step-by-step explanation:

8 0
3 years ago
The Wall Street Journal Corporate Perceptions Study 2011 surveyed readers and asked how each rated the Quality of Management and
kykrilka [37]

Answer:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent

The p-value is 0 .001909. The result is significant at p < 0.05

Part b:

40 > 8.5

35> 7.5

25> 4

Step-by-step explanation:

1) Let the null and alternative hypothesis as

H0: the quality of management and the reputation of the company are independent

against the claim

Ha: the quality of management and the reputation of the company are dependent

2) The significance level alpha is set at 0.05

3) The test statistic under H0 is

χ²= ∑ (o - e)²/ e where O is the observed and e is the expected frequency

which has an approximate chi square distribution with ( 3-1) (3-1)=  4 d.f

4) Computations:

Under H0 ,

Observed       Expected E              χ²= ∑(O-e)²/e

40                      35.00                          0.71

25                      24.50                         0.01

5                         10.50                         2.88  

35                      40.00                         0.62

35                      28.0                          1.75

10                       12.00                           0.33  

25                      25.00                             0.00

10                        17.50                              3.21

<u>15                       7.50                                 7.50  </u>

<u>∑                                                               17.0281</u>

     

     

Column Totals 100 70 30   200  (Grand Total)

5) The critical region is χ² ≥ χ² (0.05)2 = 9.49

6) Conclusion:

The calculated χ² =  <u>17.0281</u>    falls in the critical region χ² ≥  9.49  so we reject the null hypothesis that  the quality of management and the reputation of the company are independent and conclude quality of management and the reputation of the company are dependent.

7) The p-value is 0 .001909. The result is significant at p < 0.05

The p- values tells that the variables are dependent.

Part b:

If we take the excellent row total = 70 and compare it with the excellent column total= 100

If we take the good row total = 70 and compare it with the good column total= 80

If we take the fair row total = 50 and compare it with the fair column total= 30

The two attributes are said to be associated if

Thus we see that ( where (A)(B) are row and columns totals and AB are the cell contents)

AB> (A)(B)/N  

40 > 1700/200

40 > 8.5

35> 1500/200

35> 7.5

25> 800/200

25> 4

and so on.

Hence they are positively associated

8 0
3 years ago
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