
The right fraction represents the percentage; 42 over 100 (100 is the total), or 0.42.
The left fraction is the part number over the whole number. The whole number is unknown, so we use 'x'.
Your answer is 75.
Answer:
Step-by-step explanation:
We khow that A is the sum of all odd numbers that are less than 100
So A= 1+3+5+...+99
We can calculate this sum without adding all this numbers one by one
A = the number of terms *( first term + last one ) over 2
To get the number of terms we substract the first term from the last term then we add one
We khow that odd numbers are wiritten this way : 2*n +1 where n is an integer
So 99= 2*49+1
1= 2*0+1
So the number of terms is : 49-0+1 =50
So A= 50*(1+99)/2 = 2500
Foloowing the same method we get :
B= (49-1+1)*(2+98)/2= 2450
A>B
To organize the expressions according to the number of terms, you should understand what a term is. A term is either a single number or variable, or numbers and variables multiplied together. Terms are separated by + or − signs. It is organized as follows:
2x2y + x2 - 3x + 4
3x + y + z
x + 2xyz
9x2yz
Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.
<h3>What is the binomial distribution formula?</h3>
The formula is:


The parameters are:
- x is the number of successes.
- n is the number of trials.
- p is the probability of a success on a single trial.
In this problem:
- 0.54% of the calls receive a busy signal, hence p = 0.0054.
- A sample of 1300 callers is taken, hence n = 1300.
The probability that at least 5 received a busy signal is given by:

In which:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).
Then:






Then:
P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

0.8295 = 82.95% probability that at least 5 received a busy signal.
More can be learned about the binomial distribution at brainly.com/question/24863377
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Step-by-step explanation:
the answer would be a. 1/3