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miskamm [114]
3 years ago
7

I need help Write a linear inequality to represent the graph

Mathematics
1 answer:
pav-90 [236]3 years ago
8 0

Answer:

y < 1/2x -5

Step-by-step explanation:

1/2 is the slope

-5 is the y intercept

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Are the answers for 1-3 correct? I need help with 4 and 5!!! Please!
vovangra [49]
1.

a. 12d² -6d

b. 6c^5 + 8c^4 -10c³

c. correct

2. 

a. correct

b. correct

c. 12r^8-6r^4 + 9r^2, then multiply the rest by -1

3. correct

4. x² + 10

5. d=4, -1/3
8 0
3 years ago
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Can someone help explain this to me?​
o-na [289]

Step-by-step explanation:

A. y-5=-4x+4

y=-4x+4+5

y= -4x +9

(0,9)(9/4,0)

8 0
3 years ago
Grandma Gertrude gave 131313 pieces of jewelry and Grandma Fien gave yyy pieces of jewelry to the Carlson sisters to divide even
alex41 [277]

Answer: (13 + y) / 5

Step-by-step explanation:

Since Grandma Gertrude gave 13 pieces of jewelry and Grandma Fien gave y pieces of jewelry to the Carlson sisters, the total jewellery given to the sisters will be:

= 13 + y

Since there are 5 Carlson sisters, the number of pieces of jewelry that each sister receive will be:

= Total jewelries / Number of sisters

= (13 + y) / 5

7 0
3 years ago
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The research funds of a certain company were divided among three departments, X, Y, and Z. Which one of the three departments re
krek1111 [17]

Answer:

Highest received is by department Y

Step-by-step explanation:

Given that the research funds of a certain company were divided among three departments, X, Y, and Z.

The research funds received by departments X and Y were in the ratio 3 to 5, respectively.

The research funds received by departments X and Z were in the ratio 2 to 1, respectively

X:Y = 3:5

X:Z = 2:1

X is common in both the equations so let us take lcd for 3 and 2 = 6

Multiply I equation by 2 and II equation by 3

X:Y = 6:10

X: Z = 6:3

Since X has the same numerical value we can combine these two tog et

X:Y: Z =6:10:3

Highest received is by department Y

4 0
3 years ago
If 4 divides a^2-3b^2, then at least one of the integers a and b is even.
OleMash [197]

Answer:

Step-by-step explanation:

Suppose, on the contrary, a and b are both odd integers, that is:

a=2n+1\\\\b=2m+1\\\\

m and n being some integers numbers.

This way you have to:

a^{2}-3b^{2}=(2n+1)^2-3(2m+1)^2=(4n^2+4n+1)-3(4m^2+4m+1)\\\\a^{2}-3b^{2}=4(n^2-3m^2+n-3m)-2=4(n(n+1)-3m(m+1))-2

The last expression cannot be divisible by 4 since 2 is not divisible by 4. The previous conclusion leads to a contradiction, which was generated from the assumption that a and b were both odd integers. In conclusion, at least one of the two a and b should be an even integer

3 0
3 years ago
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