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velikii [3]
1 year ago
12

The total amount of money (in cents) in x dimes, (x+2) nickels, and 2x quarters. The total amount of money is ____ cents. (Hint:

value of a dime is 10 cents, nickel is 5 cents, and a quarter is 25 cents.)
Mathematics
1 answer:
dolphi86 [110]1 year ago
8 0

The total amount of money is 65x + 10 cents.

<h3>Sum of coins</h3>

Given the following coins value

x dimes, (x+2) nickels, and 2x quarters

If value of a dime is 10 cents, nickel is 5 cents, and a quarter is 25 cent, the the total coin is cent is expressed as 10x + 5(x + 2) + 25(2x)

Total in cents. = 10x + 5(x + 2) + 25(2x)

Total in cents = 10x + 5x + 10 + 50x

Simplify

Total in cents = 65x + 10

Hence the total amount of money is 65x + 10 cents.

Learn more on cents to dimes here: brainly.com/question/6810598

#SPJ1

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What two numbers add to 18 and multiply to 82
Feliz [49]
The answers are complex numbers...

Here's why...

---------

p+q=18

pq=82

---------

Therefore:

p=18-q

p=82/q

------------

Therefore:

18-q=82/q

q(18-q)=q(82/q)

18q-q²=82

(-1)(18q-q²)=82(-1)

q²-18q=-82

(q-9)²-9²=-82

(q-9)²-81=-82

(q-9)²=-82+81

(q-9)²=-1

q-9=-√(-1)=-i

q-9=√(-1)=i

-----------

Therefore:

q=9-i

q=9+i

-------------

ANSWERS:

When q=9-i, p=9+i

When q=9+i, p=9-i

-----------

Proof:

p+(9-i)=18

p+9-i=18

p=18-9+i

p=9+i

....

p+(9+i)=18

p+9+i=18

p=18-9-i

p=9-i

--------------

More proofs:

p=82/(9+i)

p=(82/(9+i))*((9-i)/(9-i))

p=(82(9-i))/(81-9i+9i-i²)

p=(82(9-i))/(81-(-1))

p=(82(9-i))/82

p=9-i

---------------

p=82/(9-i)

p=(82/(9-i))*((9+i)/(9+i))

p=(82(9+i))/(81+9i-9i-i²)

p=(82(9+i))/(81-(-1))

p=(82(9+i))/82

p=9+i
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