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Mamont248 [21]
3 years ago
12

Janice needs at least $125 to buy a new bike. She already has $35 and plans to save $10 every week. If w represents the number o

f weeks Janice saves money, which inequality represents how many weeks it will take her to save enough money to buy a bike?​
Mathematics
1 answer:
Vilka [71]3 years ago
4 0

Answer:

10w + 35 >= 125

Step-by-step explanation:

She saves $10m per week. That is 10w.

She already has $35, so add 35 to 10w.

10w + 35 >= 125

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Four times a number is the same as the difference of three times a number and four find the number round your answer to the near
maksim [4K]

Answer:

4

Step-by-step explanation:

Its four because:

4 x 3 = 12

12 + 4 = 16

4 x 4 = 16

Four times times three plus four is like saying four times four.

4 0
3 years ago
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Evaluate: 3x + 6x for x=-1
bekas [8.4K]

Answer:

-9

Step-by-step explanation:

you put in -1 where there is an x in the equation

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-3 - 6

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The speed of a ship is given by d3, where d is the distance the ship travels in 3 hours. if the ship travels 48 miles in 3 hours
Kay [80]
Hello there! Thank you for asking your question here at Brainly! I will be assisting you today with answering this problem, and will teach you how to handle it on your own in the future.

First, let's take a look at our problem.
"The speed of a ship is given by D3, where D is the distance the ship travels in 3 hours. If the ship travels 48 miles in 3 hours, what is the speed of the ship?"

To solve for this, we need to understand the formula for speed.
The formula for speed is:
Speed = \frac{Distance}{Time}

Now that we have our formula, let's define our variables.

So, we have our distance, 48 miles, and our time, 3 hours.
Let's plug in these numbers to the formula.
Speed = \frac{48}{3}

Simplify the fraction to get the speed.
\frac{48}{3} = 16.

Your final equation is:
Speed = 16.

Our final answer is 16 mph.

I hope this helps!
4 0
3 years ago
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A particle moves on a coordinate line with an acceleration at time t seconds of e^t/2 m/sec^2. At t=0 the particle is at the ori
castortr0y [4]
Hello,

A) a=e^ \frac{t}{2} \\\\

v(t)=\int\ a\ dt=\int\ e^ \frac{t}{2}\ dt=2*e^ \frac{t}{2}+C\\\\v(0)=-4\\
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\boxed{v(t)= 2*e^ \frac{0}{2}-6}\\\\





B)
2*e^ \frac{t}{2}-6=0\\\\

e^ \frac{t}{2}=3\\\\

t=2*ln(3)\approx{2,19722...}\\



C)

x(t)=\int_0^6(2*e^ \frac{t}{2}-6})\ dt=\left[4*e^ \frac{t}{2}-6t\right]_0^6\\\\ =e^3-36-4=4e^3-40\approx{40.3421...}\\\\



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3 years ago
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2x^2 + 9x + 4 = 0

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x1 = - 1/2

x2 = - 4

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4 years ago
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