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2 years ago

15

Find the equation of the line through point (2,−4) and parallel to −6x+2y=4. Use a forward slash (i.e. "/") for fractions (e.g.

1/2 for 12). Y=

1 answer:

chubhunter [2.5K]2 years ago

5 0

Answer:

y = 3x - 10

Step-by-step explanation:

Step 1: Rewrite 1st equation

2y = 6x + 4

y = 3x + 4

Step 2: Find 2nd equation

y = 3x + b

-4 = 3(2) + b

-4 = 6 + b

b = -10

Step 3: Rewrite 2nd equation

y = 3x - 10

And we have your parallel equation!

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The position of an object moving along an x axis is given by x = 3.24 t - 4.20 t2 + 1.07 t3, where x is in meters and t in secon

Pavel [41]

Answer and explanation:

Given : The position of an object moving along an x axis is given by $x=3.24t-4.20t^2+1.07t^3$ where x is in meters and t in seconds.

To find : The position of the object at the following values of t :

a) At t= 1 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(1)=3.24(1)-4.20(1)^2+1.07(1)^3$

$x(1)=3.24-4.20+1.07$

$x(1)=0.11$

b) At t= 2 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(2)=3.24(2)-4.20(2)^2+1.07(2)^3$

$x(2)=6.48-16.8+8.56$

$x(2)=-1.76$

c) At t= 3 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(3)=3.24(3)-4.20(3)^2+1.07(3)^3$

$x(3)=9.72-37.8+28.89$

$x(3)=0.81$

d) At t= 4 s

$x(t)=3.24t-4.20t^2+1.07t^3$

$x(4)=3.24(4)-4.20(4)^2+1.07(4)^3$

$x(4)=12.96-67.2+68.48$

$x(4)=14.24$

(e) What is the object's displacement between t = 0 and t = 4 s?

At t=0, x(0)=0

At t=4, x(4)=14.24

The displacement is given by,

$\triangle x=x(4)-x(0)$

$\triangle x=14.24-0$

$\triangle x=14.24$

(f) What is its average velocity from t = 2 s to t = 4 s?

At t=2, x(2)=-1.76

At t=4, x(4)=14.24

The average velocity is given by,

$\triangle x=x(4)-x(2)$

$\triangle x=14.24-(-1.76)$

$\triangle x=14.24+1.76$

$\triangle x=16$

4 0

2 years ago

Two perpendicular lines intersect on the -axis. The equation of one line is y- 4x-6=0. Determine the equation of the other line.

Kay [80]

Answer:

y = $-\frac{1}{4}$ x + 6 or y = $-\frac{1}{4}$ x - 0.375

Step-by-step explanation:

For 2 lines to be perpendicular, their slopes must be <u>negative reciprocals</u>. In order to find the perpendicular of y - 4x - 6 = 0:

SLOPE INTERCEPT FORM: y = 4x + 6

SLOPE OF LINE A: m=4

SLOPE OF LINE B (the one you are looking for): m= $-\frac{1}{4}$

Since I don't know if you meant that they intercept on the x or y axis I will do both.

<u>y-axis</u>

y-6= $-\frac{1}{4}$ (x-0)

y = $-\frac{1}{4}$ x+6

<u>x-axis</u>

y-0= $-\frac{1}{4}$ (x-1.5)

y= $-\frac{1}{4}$ x-0.375

7 0

2 years ago

62.8 in scientific notation

bearhunter [10]

Answer:

6.28 x 10²

Step-by-step explanation:

first number must be greater than or equal to 1 and less than 10

if you move the decimal to the left you need to increase the power of ten by one for each move

if you move the decimal to the rightt you need to decrease the power of ten by one for each move

8 0

2 years ago

Which of the following applies the law of cosines correctly and could be solved to find m∠Q? ANSWERS: A) 302 = 182 + 172 – 2(18)

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

Law of cosines: c^2 = a^2 + b^2 − 2ab cos(C)

Used to find: the angles of a triangle when we know all three sides

We are looking for: Angle Q. The side opposite Angle Q (30) can be c. Line segments RQ and QS are a(17) and b(18).

30^2 = 18^2 + 17^2 - 2(17)(18) cos (q)

4 0

2 years ago

What is 100 times the value of 79.47?

tino4ka555 [31]

100 times the value of 79.47 will be equivalent to 7947 (seven thousand nine hundred seventy-four)

<h3>How to find out 100 times the value given?</h3>

This answer can be found by using multiplication. As shown below:

79.47 x 100 = 7947

Moreover, considering this is a decimal number, another method can be applied. This method implies moving the comma or period found in the decimal number one space to the right for every 0 if you are multiplying it by 10, 100, 1000, etc.

79.47 x 100 = 7947

Learn more about multiplication in: brainly.com/question/5992872

#SPJ1

7 0

1 year ago