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3 years ago

Helpppp plsssssssssss

Mathematics

1 answer:

larisa86 [58]3 years ago

3 0

Answer:udhufhdfhjfjfdhuhudhfjdh.

Step-by-step explanation:fuidhfshjsahsj.

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HELPPPPPPPPP i have the most trouble with math what’s the answer??

weqwewe [10]

Answer: Third option

Step-by-step explanation:

Remember that:

$\sqrt[n]{x^n}=x$

And the Product of powers property:

$(a^m)(a^n)=a^{(m+n)}$

The expression is:

$\sqrt[4]{\frac{3}{2x}}$

To simplify this expression, you need to multiply the denominator and the numerator by $2^3x^3$ . Then:

$\frac{\sqrt[4]{3}}{\sqrt[4]{2x}}=\frac{\sqrt[4]{3(2^3x^3)}}{\sqrt[4]{2x(2^3x^3)}}$

Simplifiying, you get:

$\frac{\sqrt[4]{3(8x^3)}}{\sqrt[4]{2x(2^3x^3)}}=\frac{\sqrt[4]{24x^3}}{\sqrt[4]{2^4x^4}}=\frac{\sqrt[4]{24x^3}}{2x}$

7 0

4 years ago

Please help!! And pls show work

coldgirl [10]

<h3>The answer to your question is k (-3) = 21!</h3>

Here's how I got this answer:

K(a) = 2a^2 - a

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3K (-3) = 18 + 3

K(a) = 2a^2 - a K(-3) = 2(-3)^2 - (-3)K(-3) = 2(9) + 3K (-3) = 18 + 3K (-3) = 21

I hope this helps!

Also sorry for the late answer, I just got the notification that you replied to my comment, I hope I came in time!

8 0

4 years ago

Which of the following numbers are perfect squares? 35 145 169 18

Ann [662]

Answer 169

This is because 13x13=169

7 0

3 years ago

Read 2 more answers

Which number produces an irrational number when added to 1/3?

fiasKO [112]

Any irrational number will make an irrational number when added to 1/3.

Hope this helped :)

6 0

3 years ago

Read 2 more answers

Please help!! Find BD

Temka [501]

Answer: $8\sqrt{2}$

==========================================================

Work Shown:

Focus entirely on triangle ABD (or on triangle BCD; both are identical)

The two legs of this triangle are AB = 8 and AD = 8. The hypotenuse is unknown, so we'll say BD = x.

Apply the pythagorean theorem.

$a^2 + b^2 = c^2\\\\c = \sqrt{a^2 + b^2}\\\\x = \sqrt{8^2 + 8^2}\\\\x = \sqrt{2*8^2}\\\\x = \sqrt{8^2*2}\\\\x = \sqrt{8^2}*\sqrt{2}\\\\x = 8\sqrt{2}\\\\$

So that's why the diagonal BD is exactly $8\sqrt{2}\\\\$ units long

Side note: $8\sqrt{2} \approx 11.3137$

6 0

3 years ago