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3 years ago

You can view the question below.

Mathematics

1 answer:

ahrayia [7]3 years ago

7 0

The answer is B I have provided a picture to show the solving steps

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I need help with this thanks

Elina [12.6K]

Answer:

n ÷ 2

Step-by-step explanation:

if you insert a 12 for 'n', the corresponding value below would be 12÷2, or 6

this follows the pattern in the table

7 0

3 years ago

Write 14/√2 + √50 in the form b√2 where b is an integer.

kifflom [539]

Answer:

$12 \sqrt{2}$

Step-by-step explanation:

Taking the terms one at a time,

$\frac{14}{ \sqrt{2} } \\ \frac{14 * \sqrt{2} }{ \sqrt{2} * \sqrt{2} } \\ \frac{14 \sqrt{2} }{2} \\ 7 \sqrt{2}$

$\sqrt{50} \\ \sqrt{25 * 2} \\ \sqrt{25}* \sqrt{2} \\ 5 * \sqrt{2} \\ 5 \sqrt{2}$

Adding the terms, you have;

$7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}$

Hope it helps!

I'm out!

3 0

3 years ago

Read 2 more answers

Triangle PIG was rotated to create triangle P'I'G'. Describe the transformation using details and degrees.

insens350 [35]

The rotation of the triangle is 270 degrees clockwise, or 90 degrees counterclockwise. Most commonly, clockwise measurements are used when it comes to rotations.

I hope this helped. Let me know if I was correct please.

6 0

3 years ago

The cost (in dollars) of a custom made sweatshirt is represented by 3.5n +29.99, where n is the number of different colors in th

juin [17]

Answer:

$52.5n+449.85$

Step-by-step explanation:

The cost is given for <em>1 sweatshirt</em>. To find the cost of 15 sweatshirts, we need to multiply the expression by 15. Let's do this:

$15(3.5n+29.99)\\=15(3.5n+29.99)\\=15(3.5n)+15(29.99)\\=52.5n+449.85$

This is the expression that represents the cost of 15 sweatshirts.

8 0

3 years ago

If a and b are rational numbers and 6/(3√2-2√3 ) = a √2-b √3 , then find the values of a and b.

eduard

Answer:

=3–√−13–√+1⋅3–√−13–√−1

=(3–√−1)23–√2−12

=3–√2+12−23–√3−1

=4−23–√2

2−13–√

a=2,b=−1.

Step-by-step explanation:

6 0

3 years ago

You can view the question below. ​

You can view the question below.