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frozen [14]
2 years ago
9

You can view the question below. ​

Mathematics
1 answer:
ahrayia [7]2 years ago
7 0
The answer is B I have provided a picture to show the solving steps

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1 point
mrs_skeptik [129]

you divied the 10.30 by 10 and get 1.03

8 0
3 years ago
17 divided by what equals 43
irina [24]
You have to multiply 43 by 17 to get the missing number.

8 0
3 years ago
Tuition at Greenery Grove College costs $9,100 this year. Elise's parents have agreed to pay
kirill115 [55]

Answer:

2275

Step-by-step explanation:

9100/4 = 2275

this is why you don't go to college, you get boatloads of debt

8 0
3 years ago
A triangle has the side lengths 5,7 and 11
Assoli18 [71]

To solve this problem you use the "Triangle Inequality Theorem" it states that: any side of a triangle is always shorter than the sum of the other two sides. 

Using this theorem we check each side 

5+7=12: this is greater than the other side which is 11, so this works 

11+7= 18: this is greater than the other side which is 5, so this works 

5 + 11= 16: this is greater that the other side which is 7, so this works 

4 0
3 years ago
Surface area of a pyramid
Ede4ka [16]

The general formula for the total surface area of a regular pyramid is T. S. A. =12pl+B where p represents the perimeter of the base, l the slant height and B the area of the base

To find the surface area of a regular triangular pyramid, we use the formula SA = A + (3/2)bh, where A = the area of the pyramid's base, b = the base of one of the faces, and h = height of one of the faces.

We can also label the length (l), width (w), and height (h) of the prism and use the formula, SA=2lw+2lh+2hw, to find the surface area.

To find surface area for a rectangular prism, use the formula SA = 2ab + 2bc + 2ac, where a is the width, b is the height, and c is the length. If you're trying to find the surface area of a triangular prism, use the formula SA = 2a + ph, where a is the area of the triangle, p is the perimeter, and h is the height

Hope that was helpful.Thank you!!!

7 0
3 years ago
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