All categories

2 years ago

I need help with this asap

Mathematics

2 answers:

shepuryov [24]2 years ago

6 0

Answer:

option C

Step-by-step explanation:

Because it increases with the same rate of 22.5.

To check that you can find the slope of the graph using two points from the graph.

I will take (1, 22.5) and (2, 45).

$slope = \frac{y_2-y_1}{x_2-x_1} = \frac{45-22.25}{2-1} = 22.5$

Aleksandr [31]2 years ago

3 0

I need point sorry for wasting your time

You might be interested in

Question

statuscvo [17]

Answer:

he used 1/4 yards per skhirt

7 0

3 years ago

Quinzel earns $1,254 each month. His total deductions are 20% of his pays. How much is deducted from his pay each months?

Makovka662 [10]

The monthly deduction is $250.80

Given:

monthly pay = 1,254

monthly rate of deduction = 20%

Simply multiply the rate to the monthly pay to get the value of the deduction.

1,254 * 20% = 250.80 deduction 1,254 - 250.80 = 1,003.20 take home

7 0

2 years ago

Katie jogged 2.4 miles on Monday, 3.7 miles on Tuesday, and 2.9 miles on Wednesday. How many miles did Katie jog on Thursday if

iVinArrow [24]

12.1 total
- 2.4 Monday
3.7 Tuesday
2.9 Wednesday
_______________
3.1 Thursday

8 0

3 years ago

Read 2 more answers

Which diagram matches the following situation?

Alika [10]

Answer:

the second one. AKA the right top one

Step-by-step explanation:

7 0

2 years ago

Which statement correctly relates the standard deviation of the two data sets below? Data set 1 Data set 2 1 2 2 2 3 3 3 3 6 4 4

Tems11 [23]

Answer:

C.) The standard deviation of Data Set 1 is about twice the standard deviation of Data Set 2.

Step-by-step explanation:

Data Set 1: 1,2,3,3,6
Data Set 2: 2,2,3,3,4,4

Data Set 1

$\mu =\dfrac{1+2+3+3+6}{5}= \dfrac{15}{5}=3$

$S$tandard Deviation, \sigma =\sqrt{\dfrac{\sum (x-\mu)^2}{N}}$

$\sigma =\sqrt{\dfrac{(1-3)^2+(2-3)^2+(3-3)^2+(3-3)^2+(6-3)^2}{5}}\\=\sqrt{\dfrac{4+1+0+0+9}{5}}\\=\sqrt{\dfrac{14}{5}}\\\\=1.67$

Data Set 2

$\mu =\dfrac{2+2+3+3+4+4}{6}= \dfrac{18}{6}=3$

$\sigma =\sqrt{\dfrac{(2-3)^2+(2-3)^2+(3-3)^2+(3-3)^2+(4-3)^2+(4-3)^2}{6}}\\=\sqrt{\dfrac{1+1+0+0+1+1}{6}}\\=\sqrt{\dfrac{4}{5}}\\\\=0.89$

0.89 X 2=1.78 which is close to 1.67

Therefore, the standard deviation of Data Set 1 is about twice the standard deviation of Data Set 2.

8 0

2 years ago