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Feliz [49]
3 years ago
5

In the beginning of the study, a randomly selected group of 121 students scored an average of 252 words per minute on the readin

g speed test. Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M
Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

Step-by-step explanation:

We use the central limit theorem to solve this question.

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a sample size larger than 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

So

Since the sample size is larger than 30, the cognitive psychologist can assume that the sampling distribution of M will be approximately normal.

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2.n=2.n+3

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Step-by-step explanation:

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Help me please,Thanks
Ugo [173]

The answer to this question would be the last choice (this data has no outliers)

Explanation: The reason for this is that an outlier is basically any number or value that kind of stands off or is very separated from a set of data.

For example, if I had the numbers 1,2,3,2,9,5,7,5,8,4 and 47, 47 would definitely be an outlier as it's significantly greater than the rest of the data.

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5 0
3 years ago
Factor 8x^3y + 38x^2y - 10xy
Sophie [7]

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2xy(x+5)(4x−1)

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1 Find the Greatest Common Factor (GCF).

GCF = 2xy

2 Factor out the GCF. (Write the GCF first. Then, in parentheses, divide each term by the GCF.)

2xy (8x^3y + 38x^2y/2xy + −10xy/2xy)

3 Simplify each term in parentheses.

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4 Split the second term in 4x^2+19x-5 into two terms.

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5 Factor out common terms in the first two terms, then in the last two terms.

2xy(4x(x+5)−(x+5))

6 Factor out the common term x+5.

2xy(x+5)(4x−1)

7 0
2 years ago
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