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AnnZ [28]
3 years ago
7

This is a rational equation i don't understand lol -2 1/4 = 2w

Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

w=-9/8

Step-by-step explanation:

We are given the equation -2 \frac{1}{4} = 2w. To solve this equation, we can divide both sides by 2 to get that w = -2\frac{1}{4} \div 2 = -\frac{9}{8}.

Aleksandr-060686 [28]3 years ago
4 0

Answer:

w = - \frac{9}{8}

Step-by-step explanation:

Given

- 2 \frac{1}{4} = 2w ( change the mixed number to an improper fraction )

- \frac{9}{4} = 2w ( multiply both sides by 4 to clear the fraction )

- 9 = 8w ( divide both sides by 8 )

- \frac{9}{8} = w

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Will award brainliest!
Lostsunrise [7]
<h3>✽ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ✽</h3>

➷ Use the geometry rule:

(|(20(-2) - 21(3) - 42|) / square root of 20^2 + (-21)^2

Now you get:

(x + 2)^2 + (y - 3)^2 = 5^2

This can also be written as:

x^2 + 4x + y^2 - 6y - 12.

It would be option B

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4 0
3 years ago
A physical education department wanted a single test of upper body strength that was easy to administer. Dips on the parallel ba
Gennadij [26K]

Answer:

24.23 ; 13.47 ; 0.782 ; p value < 0.00001 ;7.45

Step-by-step explanation:

Given that :

ΣX = 3,416, ΣY = 1,899, SDX = 8.84, SDY = 4.70, ΣZXZY = 109.416

Sample size, N = 141

Mean of X:

£X / N = 3416 / 141 = 24.23

Mean of Y:

£Y / N = 1899 / 141 = 13.47

B.) Correlation between the 2 variables :

£ZXZY / N - 1

= 109.416 / 140

= 0.782

C.)

Level of significance and p value :

T = [Rsqrt(n-2)] ÷ sqrt(1 - R²)

T = [0.782 * sqrt(139)] ÷ sqrt(1-0.782^2)

T = 14.79

P value from Tscore calculator

Df = 141 - 2 = 139 ; α = 0.05

Pvalue = 0.00001

Pvalue < α ; Hence, a significant positive relationship exists.

To obtain regression model :

Slope = £ZXZY / SDX²

m = 109.416 / 8.84^2 = 1. 4

yintercept = meanY - slope*x

yintercept = 13.47 - 1.4*24.3

yintercept = - 20.55

Equation in slope intercept form:

y = mx + c

y = 1.4x - 20.55

For x = 20

y = 1.4(20) - 20.55

y = 7.45

5 0
3 years ago
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