Find the slope of the following graph a) 1/2 b) 2 c) -2 d) -1/2
1 answer:
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For this case we have the following function:
By definition, we have that a linear equation is of the form
On the other hand, a quadratic equation is of the form
Then, the given equation is not a linear equation, it is not of the form
Answer:
No, the equation is not linear. It is not of the form
Answer:
Step-by-step explanation:
We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).
Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus
Join JH and GI such that they form the diagonals of the quadrilateral.Now,
JH= and
GI=
Now, mid point of JH=
=
Mid point of GI=
Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.
Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.
Thus, From ΔGIJ, we have
(1)
Now, JI= and GJ=
Substituting these values in (1), we get
Thus, GIJ is a right angles triangle.
Hence, GHIJ is a rectangle.
Also, The diagonals GI= and HJ=
are equal, thus, GHIJ is a rectangle.