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3 years ago

What is the solution to this equation -8 and one third y equals 2

Mathematics

1 answer:

omeli [17]3 years ago

6 0

I hope this helps you

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Please help with geometry,will give brainliest

wolverine [178]

Answer:

Step-by-step explanation:

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3 years ago

Help please! 10 points for this question

vichka [17]

Bottom left. Because of th eminus sign, the v curve is "upside-down" and because of the +1, its function value peak is at 1

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3 years ago

Suppose there were m married couples, but that d of these 2m. people have died, Regard the d deaths as striking the 2m people at

iren2701 [21]

The function that represents surviving people are X = 2m - d

Given that there are m married couples and d of the 2m of these couples have died, the total people that remain is expressed as:

Total people remaining = Total married couple - those that died

Total married couple = 2m

Total people that died = d

Taking the difference to get the remaining people;

Total people remaining = 2m - d

Hence the function that represents surviving people are X = 2m - d

Learn more on difference here: brainly.com/question/2605546

6 0

2 years ago

What will be the firm's quick ratio after Nelson has raised the maximum amount of short-term funds? Do not round intermediate ca

Marysya12 [62]

Based on the short-term debt that Nelson raises, the firm's quick ratio will be 1.204.

<h3>What is the firm's quick ratio?</h3><h3 />

First, find the maximum amount of short-term funds that Nelson can raise?

Assuming this amount is x, we can find it with the current ratio formula:

Current ratio = Current assets / Current liabilities

2 = (1,260,000 + x) / ( 450,000 + x)

x = $360,000

The quick ratio would therefore be:

= ( New Current assets - New inventory) / New current liabilities

= ( (1,260,000 + 360,000) - (285,000 + 360,000) ) / (450,000 + 360,000)

= 1.204

Find out more on quick ratio at brainly.com/question/13917900.

#SPJ1

5 0

2 years ago

<img src="https://tex.z-dn.net/?f=prove%20that%5C%20%20%5Ctextless%20%5C%20br%20%2F%5C%20%20%5Ctextgreater%20%5C%20%5Cfrac%20%7B

inysia [295]

$\large \bigstar \frak{ } \large\underline{\sf{Solution-}}$

Consider, LHS

$\begin{gathered}\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {sec}^{2}x - {tan}^{2}x = 1 \: \: }} \\ \end{gathered} \\ \\ \text{So, using this identity, we get} \\ \\ \begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - ( {sec}^{2}\theta - {tan}^{2}\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

We know,

$\begin{gathered}\boxed{\sf{ \:\rm \: {x}^{2} - {y}^{2} = (x + y)(x - y) \: \: }} \\ \end{gathered} \\$

So, using this identity, we get

$\begin{gathered}\rm \: = \:\dfrac { \tan \theta + \sec \theta - (sec\theta + tan\theta )(sec\theta - tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered}$

can be rewritten as

$\begin{gathered}\rm\:=\:\dfrac {(\sec \theta + tan\theta ) - (sec\theta + tan\theta )(sec\theta -tan\theta )} { \tan \theta - \sec \theta + 1 } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac {(\sec \theta + tan\theta ) \: \cancel{(1 - sec\theta + tan\theta )}} { \cancel{ \tan \theta - \sec \theta + 1} } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:sec\theta + tan\theta \\\end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1}{cos\theta } + \dfrac{sin\theta }{cos\theta } \\ \end{gathered} \\ \\ \\\begin{gathered}\rm \: = \:\dfrac{1 + sin\theta }{cos\theta } \\ \end{gathered}$

<h2>Hence,</h2>

$\begin{gathered} \\ \rm\implies \:\boxed{\sf{ \:\rm \: \dfrac { \tan \theta + \sec \theta - 1 } { \tan \theta - \sec \theta + 1 } = \:\dfrac{1 + sin\theta }{cos\theta } \: \: }} \\ \\ \end{gathered}$

$\rule{190pt}{2pt}$

5 0

2 years ago