For part A: two transformations will be used. First we will translate ABCD down 3 units: or the notation version for all (x,y) → (x, y - 3) so our new coordinates of ABCD will be:
A(-4,1)
B(-2,-1)
C(-2,-4)
D(-4,-2)
The second transformation will be to reflect across the 'y' axis. Or, the specific notation would be: for all (x,y) → (-x, y) New coordinates for A'B'C'D'
A'(4,1)
B'(2,-1)
C'(2,-4)
D'(4,-2)
Part B: The two figures are congruent.. We can see this a couple of different ways.
- first after performing the two transformations above, you will see that the original figure perfectly fits on top of the image.. exactly the same shape and size.
- alternatively, you can see that the original and image are both parallelograms with the same dimensions.
The coefficient of y∧15×∧2 in expansion of (y∧3+x)∧7 is (15×2)+(3×7)= 51
Answer:
Step-by-step explanation:
f(x) = 4-x
g(x) = h
+k
g(f(x)) = 2-16x+26
so put f(x) in g(x)
h
+k
h((4-x)(4-x) + k
h(-8x+16)+k
if h = 2 , then
2-16x+32 + k
and we want 26 instead of 32 so subtract 6 so K = (-6)
2-16x+32 + (-6)
2-16x+32 - 6
2-16x+26
h=2
k=(-6)
2x-2>-12
2x>-10
x>-5
hope this helps!
