2 tens, and 8 ones. I say this because 20 = 10 + 10 so, two tens. 8= 1+1+1+1+1+1+1+1 so, eight ones.
Answer:
10) 9x - 2° = 5x + 54° (corresponding angles are equal)
9x - 5x = 54 + 2
4x = 56
x = 56/4
x = 14°
10y + 6° = 9x - 2° (linear pair)
10y + 6° = 9(14)° - 2°
10y + 6° = 126° - 2°
10y + 6° = 124°
10y = 124° - 6°
10y = 118
y = 118/10
Sorry, i don't know how to do the 11th question
but hope this helps you!
Given:
mean = 64
standard deviation = 6
sample size = 50
Standard error of the sample mean = standard deviation / √sample size
Standard error = 6 / √50 = 6/7.07 =<span> 0.85</span>
Option 1:
<span>Measuring the heights of every fiftieth person on the school roster to determine the average heights of the boys in the school
</span>
Comment: this might not be a good idea for fairness as we only wish to determine average height of the boys. Taking a group of 50 people randomly, might not give us the same number of boys every time.
Option 2:
<span>Calling every third person on the soccer team’s roster to determine how many of the team members have completed their fundraising assignment
Comment: The context doesn't seem to need a sampling. The number of players in a soccer team is considerably small. We can find exact data by asking in person.
Option 3:
</span><span>
Observing every person walking down Main Street at 5 p.m. one evening to determine the percentage of people who wear glasses
</span>
Comment: To get a more accurate result and fairer sampling, the period of observing could have been longer, for example, observing for 12 hours on that day, or an alternative is to observe at 5 pm for 7 days in a row. It could happen that no one walking down the Main street precisely at 5 pm wears glasses, or it could happen the other way around.
Option 4:
<span>Sending a confidential e-mail survey to every one-hundredth parent in the school district to determine the overall satisfaction of the residents of the town taking a poll in the lunch room (where all students currently have to eat lunch) to determine the number of students who want to be able to leave campus during lunch.
Comment: This sampling does fairly represent the population, although it might be an idea to scale down the sample population, i.e. every fiftieth parent.
Answer: Option 4</span>
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