Answer: There is no question so I don't know how to answer your question
Step-by-step explanation:
X² + 3x = 10
Convert to standard form.
x² + 3x - 10 = 0
factor x² = x * x
factor -10 = 5 * -2
(x + 5) (x - 2) = 0
x(x -2) + 5(x-2) = 0
x² - 2x + 5x - 10 = 0
x² + 3x - 10 = 0
x + 5 = 0 x² + 3x = 10
x = -5 -5² + 3(-5) = 10
25 - 15 = 10
10 = 10
x - 2 = 0 x² + 3x = 10
x = 2 2² + 3(2) = 10
4 + 6 = 10
10 = 10
Answer:
Yes, only one range value exists for each domain value.
Answer:
Step-by-step explanation:
To get the value of the expressions in list A and list B we will substitute y = 5 in each expression.
List A List B
1). 6 + 6y = 6 + 6(5) = 36 6y - 6 = 6(5) - 6 = 24
2). 6(y - 1) = 6(5 - 1) = 24 6(y + 1) = 6(5 + 1) = 36
3). 6y + 1 = 6(5) + 1 = 31 1 + 6y = 1 + 6(5) = 31
Therefore, (6 + 6y) is equivalent to 6(y + 1)
6(y - 1) is equivalent to (6y - 6)
(6y + 1) is equivalent to (1 + 6y)
