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3 years ago

Rocky is building a wall.

Mathematics

2 answers:

tatyana61 [14]3 years ago

8 0

Answer:

20 packs

Step-by-step explanation:

2000 / 100 = 20 packs

Ivenika [448]3 years ago

6 0

Answer

20 packs
Explanation
Bc yeah<3

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Find the measure of angle x in the figure below: (1 point) Two triangles are shown such that one triangle is inverted and share

Elena L [17]

75°+75°=150°
angles in a triangle add up to 180°
180°-150°=30°
c) x=30°

5 0

3 years ago

Find X if m/_ UVH=50°, m/_HVW=25x-5, and m/_ UVW = 35x-5.

ra1l [238]

Step-by-step explanation:

first you have to solve for x

35x - 5=50

35-35x-5= 50-35

x-5=15

x- 5÷5=15÷5

x=3

Now we have to substitute x into the equation.

35×(3)-5=

175-5=170

angle UVW= 170

to find angle HUW instead of solving the equation just subtract 170 from 50 and you will get 120.

angle UVH=50

angle HUW=120

angle UVW=170

I hope this helps srry it took so long but gn and gl.

7 0

3 years ago

Which is greater than or less than

poizon [28]

Answer:

C. -2/3 < -0.8

F. -3/5 < -0.35

Therefor, -2/3 is less than -0.8.

And, -3/5 is also less than -0.35.

Also, you could turn the fractions into decimals to make your life easier for example, -3/5 into decimal form is -0.6.

And -2/3 into decimal form is -0.6666

* Hopefully this helps:) Mark me the brainliest:)!!

3 0

3 years ago

Answer for a cookie ;)

Anuta_ua [19.1K]

Answer:

Step-by-step explanation:

but i will still take the cookie

4 0

3 years ago

A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru

Viktor [21]

Answer:

1) $S = 2\cdot w\cdot l - 8\cdot x^{2}$ , 2) The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$ , 3) $S = 176\,in^{2}$ , 4) $x \approx 4.528\,in$ , 5) $S = 164.830\,in^{2}$

Step-by-step explanation:

1) The function of the box is:

$S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)$

$S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w$

$S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x$

$S = 2\cdot w\cdot l - 8\cdot x^{2}$

2) The maximum cutout is:

$2\cdot w \cdot l - 8\cdot x^{2} = 0$

$w\cdot l - 4\cdot x^{2} = 0$

$4\cdot x^{2} = w\cdot l$

$x = \frac{\sqrt{w\cdot l}}{2}$

The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$

3) The surface area when a 1'' x 1'' square is cut out is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}$

$S = 176\,in^{2}$

4) The size is found by solving the following second-order polynomial:

$20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}$

$20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}$

$8\cdot x^{2} - 164\,in^{2} = 0$

$x \approx 4.528\,in$

5) The equation of the box volume is:

$V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x$

$V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x$

$V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}$

$V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}$

$V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}$

The first derivative of the function is:

$V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}$

The critical points are determined by equalizing the derivative to zero:

$12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0$

$x_{1} \approx 4.952\,in$

$x_{2}\approx 1.548\,in$

The second derivative is found afterwards:

$V'' = 24\cdot x - 78\,in$

After evaluating each critical point, it follows that $x_{1}$ is an absolute minimum and $x_{2}$ is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

$x \approx 1.548\,in$

The surface area of the box is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}$

$S = 164.830\,in^{2}$

4 0

3 years ago