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irina1246 [14]
2 years ago
11

Rocky is building a wall.

Mathematics
2 answers:
tatyana61 [14]2 years ago
8 0

Answer:

20 packs

Step-by-step explanation:

2000 / 100 = 20 packs

Ivenika [448]2 years ago
6 0
Answer

20 packs
Explanation
Bc yeah<3
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Write in slope-intercept form an equation of a line that passes through the given points. (1,6) and (3,2)
Nataliya [291]

Answer:

The answer to your proble I'm slow intercept from is y=-2x+8

Step-by-step explanation:

4 0
3 years ago
The graph shown compares the rent Andrew and Dave pay for renting bikes from different stores
Dmitry_Shevchenko [17]

Answer:I don’t know either

Step-by-step explanation:

5 0
3 years ago
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What is the following product
dangina [55]

Option B is correct.

Step-by-step explanation:

We need to solve: \sqrt[3]{x^2}\sqrt[4]{x^3}

We know that: \sqrt[n]{x}\sqrt[b]{x} =\sqrt[n*b]{x.x}= \sqrt[n*b]{x^2}

Applying the above rule:

\sqrt[3]{x^2}\sqrt[4]{x^3}\\=\sqrt[3*4]{x^2.x^3}\\=\sqrt[12]{x^5}

So, Option B is correct.

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

  • brainly.com/question/4934417
  • brainly.com/question/13174254
  • brainly.com/question/13174255

#learnwithBrainly

3 0
3 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
MORE MATH GENIUSES!!!!!!!!!!!!!!
Oliga [24]

Answer:

The friend caught the ball at 2 feet.

Step-by-step explanation:

1. False; the ball was not still in the air at 1 second the x-component of the vertex is 0.5.

2. False; the x-component of the vertex is 0.5

3. True; the ball was tossed at a height of 2 feet (when x=0, y=2), it is safe to assume the ball was caught at the same height.

4. False; when x = 0, y = 2.

8 0
3 years ago
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