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There are 5+6+4+3+2=20 m&m's in the bag.
Calculate in how many ways you can choose 3 m&m's from 20:

There are 6 yellow m&m's.
Calculate in how many ways you can choose 3 m&m's from 6:

The probability is the number of ways of choosing 3 m&m's from 6 m&m's divided by the number of ways of choosing 3 m&m's from 20 m&m's.

The probability is 1/57.
The third option is the right one
4n - 9 + 3n + 5 + n = 68
combine like terms
8n - 4 = 68
addition property of equations
8n = 72
division property of equality
n = 9
SIDES:
n = 9
3n + 5 = 32
[ 3(9) + 5 = 32 ]
4n - 9 = 27
[ 4(9) - 9 = 27 ]