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3 years ago

Write a problem that shows the following: 5 more than half of 6. PLZ ANSWER QUICK!!!!!!!!

Mathematics

2 answers:

DIA [1.3K]3 years ago

6 0

Answer:

Step-by-step explanation:

half of 6 is 3 and add 5 to 3

Strike441 [17]3 years ago

6 0

Answer:

3+5=8

Step-by-step explanation:

You might be interested in

Angle Q = 85° Determine angle O.

kkurt [141]

Answer:

∠O = 95°

Step-by-step explanation:

since ∠Q = 85°, arc NOP = 2(85°) = 170°

arc PQN = 360° - arc NOP

arc PQN = 360° - 170° = 190°

∠O = 1/2(arc PQN) = 1/2(190°) = 95°

4 0

3 years ago

Please help me and show your work thank you

Furkat [3]

Answer:

She has walked 7233.6 ft

Step-by-step explanation:

13.7 miles ÷ 10 = 1.37 miles

1 mile = 5280 ft

5280 x 1.37 = 7233.6 ft (or 7234 if rounded to the nearest ft)

6 0

3 years ago

Complete the statements.

spayn [35]

Answer:

1. 30

2. 150

Step-by-step explanation:

$3tan^2(x)-1 =0$

Lets assume tan(x) = u

$3u^2(x)-1 =0$

Now we solve for 'u'

add 1 on both sides

$3u^2(x) =1$ , divide both sides by 3

$u^2 = \frac{1}{3}$

Take square root on both sides

$u = +-\frac{1}{\sqrt{3} }$

We replace tan(x) for 'u'

$tan(x) = +-\frac{1}{\sqrt{3} }$

x = 30 because $tan(30) =+\frac{1}{\sqrt{3} }$ in first quadrant

x = 30 (tan is positive in first quadrant)

$tan(x) =-\frac{1}{\sqrt{3} }$

x = 150 because $tan(150) =-\frac{1}{\sqrt{3} }$ in second quadrant

tan is negative in second quadrant

4 0

3 years ago

A woman earns 2600 per month and budgets 468 per month for food what percent of her monthly income is spent on food

finlep [7]

divide food money by income:

468 /2600 = 0.18 = 18%

3 0

4 years ago

LCM of x2+5x+6 and x2-x-6 is ………………………

sergejj [24]

Answer:

$(x^2 - 9)(x + 2)$

Step-by-step explanation:

Given:

$x^2 + 5x + 6$

$x^2 - x - 6$

Required:

LCM of the polynomials

SOLUTION:

Step 1: Factorise each polynomial

$x^2 + 5x + 6$

$x^2 + 3x + 2x + 6$

$(x^2 + 3x) + (2x + 6)$

$x(x + 3) + 2(x + 3)$

$(x + 2)(x + 3)$

$x^2 - x - 6$

$x^2 - 3x +2x - 6$

$x(x - 3) + 2(x - 3)$

$(x + 2)(x - 3)$

Step 2: find the product of each factor that is common in both polynomials.

We have the following,

$x^2 + 5x + 6 = (x + 2)(x + 3)$

$x^2 - x - 6 = (x + 2)(x - 3)$

The common factors would be: =>

$(x + 2)$ (this is common in both polynomials, so we would take just one of them as a factor.

$(x + 3)$ and,

$(x - 3)$

Their product = $(x - 3)(x + 3)(x +2) = (x^2 - 9)(x + 2)$

4 0

3 years ago