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2 years ago

6

pid 2. The perimeter of triangle GHI is 40 cm. If both triangles are similar, then what is the length of JT. 15 cm 15 cm Wool 10

cm G

1 answer:

Elza [17]2 years ago

7 0

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Alex Ar [27]

She needs at least 130 points, so 130 - 75 (that she is earning from the sign up) = 65 points.

65 : 5,5 = 11,81 ≈ 12

So she has to sign up and visit he movie theatre at least 12 times to earn a movie ticket.

4 0

3 years ago

Answer this equation using pemdas pls.

aleksandr82 [10.1K]

Step-by-step explanation:

(8x3) -(6÷3)= 24 - 2

=22

Hope it helps ya

5 0

2 years ago

Read 2 more answers

Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

Length = 3/5 the width
Area = 375 in²

Let width = $x$

Therefore, length = 3/5 $x$

First create an equation for the area of the picture based on the given information for its width and length:

$\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}$

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for $x$ to find the width of the enlarged picture:

$\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}$

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of $x$ into the expression for length to find the length of the enlarged picture:

$\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}$

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

5 0

2 years ago

denis23 [38]

Answer:

Then, the object will take 29.11 min to travel $4\frac{9}{10}miles$

Step-by-step explanation:

When an object is moving at a steady speed, we can calculate the time it would take to travel a given distance using the following formula:

$time=\frac{distance}{speed}$ (equation 1)

In this particular, both the given speed and distance are mixed fractions so we'll first convert them into improper fractions to operate more easily:

$speed=10\frac{1}{10} \frac{mi}{h} =\frac{(10*10)+1}{10} \frac{mi}{h}=\frac{101}{10} \frac{mi}{h}$

$distance=4\frac{9}{10}mi=\frac{(4*10)+9}{10}mi=\frac{49}{10}mi$

So, now we can calculate the time using the equation 1:

$time=\frac{distance}{speed}=\frac{\frac{49}{10}mi }{\frac{101}{10} \frac{mi}{h} } =\frac{49*10}{101*10} h$

$time=\frac{49}{101}h=0.49h$

And, if we want the result in minutes:

$time=\frac{49}{101}h*\frac{60min}{1h} =29.11min$

Then, the object will take 29.11 min to travel $4\frac{9}{10}miles$

5 0

2 years ago

What is the base of 3^x=8

olasank [31]

Answer:

3

Step-by-step explanation:

4 0

2 years ago