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3 years ago

Classify the following triangle. Check all that apply.

Mathematics

2 answers:

sveticcg [70]3 years ago

5 0

Answer:

obtuse

Step-by-step explanation:

the angle is bigger than 90 degrees

Llana [10]3 years ago

3 0

Answer:

The answer is C) Obtuse and F) Isosceles

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the perimeter of an isosceles triangle in which the equal sides measures 12cm each and third side is 8cm_____. please show the w

KiRa [710]

Answer:

The perimeter of the isosceles triangle is 32 centimeters

Step-by-step explanation:

<em>The perimeter of any figure is </em><em>the sum of the lengths of outline sides</em>

Let us use this fact to solve our question

∵ The perimeter of the triangle is the sum of the lengths of its 3 sides

∵ The triangle is an isosceles triangle

∵ The length of each two equal sides is 12 centimeters

∵ The length of the third side is 8 centimeters

→ Add the lengths of the 3 sides

∴ The perimeter of the triangle = 12 + 12 + 8

∴ The perimeter of the triangle = 32 centimeters

∴ The perimeter of the isosceles triangle is 32 centimeters

8 0

3 years ago

The equation of line k is y=

Nina [5.8K]

Answer:

Neither parallel nor perpendicular

Step-by-step explanation:

I'm assuming you meant line k is y = 3x -2. If not, this is wrong.

For this, you need to put both lines in point-slope form, or the form that line k is already in. This means you only need to convert line m.

-2r + 6v = 18

6v = 2r + 18

v = 2/6r + 18/6

v = 1/3r + 3

Now you can answer the question.

To be parallel, lines must have the same slope (but a different y-intercept). 3 and 1/3 are not the same, so the lines are not parallel.

To be perpendicular, one line must have the opposite reciprocal (fraction flipped and + goes to - or - to +) of the other. While 3 is the reciprocal of 1/3, they are both positive, so they are not perpendicular.

To be the same line, the equations must be absolutely identical, which they aren't.

This leaves the last option: neither.

Let me know if you need a more in-depth explanation of anything here! I'm happy to help!

3 0

3 years ago

Read 2 more answers

In triangle ABC, angle bisectors line AD, line BE, and line CF meet at I. If DI = 3, BD = 4, and BI = 5, then compute the area o

Nikitich [7]

The area of triangle ABC is the amount of space on the triangle

The area of the triangle is 54.84 square units

<h3>How to determine the area of triangle ABC</h3>

Start by drawing the triangle (see attachment)

Next, calculate the measure of angle B using the following tangent ratio

$\tan(B/2) = \frac 34$

This gives

$\tan(B/2) = 0.75$

Take the arc tan of both sides

$B/2 = 36.87$

Multiply by 2

$B = 73.74$

Next, calculate the length of side AD using the following equation

$AD = \tan(B) * BD$

This gives

$AD = \tan(73.74) * 4$

$AD =13.71$

The area of the triangle is then calculated as:

$Area = AD * BD$

This gives

$Area = 13.71 * 4$

$Area = 54.84$

Hence, the area of the triangle is 54.84 square units