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babymother [125]
1 year ago
6

Find the derivative of 76x + 1 at x = 1.

Mathematics
2 answers:
Murljashka [212]1 year ago
7 0

\qquad\qquad\huge\underline{{\sf Answer}}♨

Let's solve ~

\qquad \sf   \dashrightarrow \: \dfrac{d}{dx}(76x + 1)

\qquad \sf  \dashrightarrow \:76 {x}^{1 - 1}  + 0

\qquad \sf  \dashrightarrow \:76 {x}^{0}  + 0

\qquad \sf  \dashrightarrow \:76

Here, we have got a constant number, therefore for any value of x it will be 76

Therefore, derivative of 76x + 1 at x = 1 is 76

Mamont248 [21]1 year ago
6 0

Answer:

<u>76</u>

Step-by-step explanation:

We know the rule when finding the derivative :

  • dy/dx = nxⁿ⁻¹

<u>Deriving</u>

  • dy/dx = 76x + 1
  • dy/dx = 1 * 76 * (x)¹⁻¹ + 0 * 1¹⁻¹
  • dy/dx = <u>76</u>
  • The x = 1 becomes irrelevant because there is no 'x' present in the derivative
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