Question

Find the derivative of 76x + 1 at x = 1.

Answer 1

$\qquad\qquad\huge\underline{{\sf Answer}}♨$

Let's solve ~

$\qquad \sf \dashrightarrow \: \dfrac{d}{dx}(76x + 1)$

$\qquad \sf \dashrightarrow \:76 {x}^{1 - 1} + 0$

$\qquad \sf \dashrightarrow \:76 {x}^{0} + 0$

$\qquad \sf \dashrightarrow \:76$

Here, we have got a constant number, therefore for any value of x it will be 76

Therefore, derivative of 76x + 1 at x = 1 is 76

Answer 2

Answer:

76

Step-by-step explanation:

We know the rule when finding the derivative :

• dy/dx = nxⁿ⁻¹

Deriving

• dy/dx = 76x + 1
• dy/dx = 1 * 76 * (x)¹⁻¹ + 0 * 1¹⁻¹
• dy/dx = 76
• The x = 1 becomes irrelevant because there is no 'x' present in the derivative