Let each side perpendicular to the wall be x
The parallel to the wall will be 320-2x
the area will be:
A(x)=x(320-2x)
A(x)=320x-2x^2
This is a quadratic with a =-2 and b=320
Maximum area will occur where x=-b/2a
=-320/(-2*2)
=80 ft
thus the width will be 80 ft and the length will be:
length=320-2*80=160 ft
Negative 31 because their both negatives so it's basically adding but in the end it's a negative number
Answer:
Y = 10.25 or 10.247
Step-by-step explanation:
Alright So use the Formula A^2 + B^2 = C^2
You have one leg and the hypotenuse so first you are going to find 19 ^2 = 361.
Next, you need to find 16^2 = 256.
Last but not least, you subtract the leg from the hypotenuse, which equals 361-256=105
Finally, you take 105 and find its square root.
And depending on how far you round it down, your answer would be 10.25(that is in tenths), or 10.247(which is rounded to hundredths)
Hope this helps!
Answer:
y=_10
its a very simple question
I think the answer would be c but I'm not positive
I hope I help :)
