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ASHA 777 [7]
3 years ago
8

Can someone please check answers??!

Mathematics
2 answers:
vfiekz [6]3 years ago
7 0
They all look pretty good to me, you should be fine boo xxo
Cloud [144]3 years ago
4 0
The first one is an odd function
The second one is an even function
The third one is neither odd and even function
Sorry if it’s wrong and hoped that helped
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Súčin rokov troch súrodencov je 385. Napíšte súčet ich rokov, ak počet rokov každého z nich je prvočíslo
valkas [14]

Answer:

i don't understand

4 0
2 years ago
The ratio of the number of boys to the number of girls in a dance club is 5 : 6. After 6 more boys join the club, the ratio beca
UkoKoshka [18]

44

Step-by-step explanation:

let boys be x and girls be y

x/y=5/6

x=5y/6....(1)

if 6 boys join the club that will be x+6

Therefore:

(x+6)/y=13/12

13y=12x+72

13y-12x=72

Recall x=5y/6

Therefore:

13y-12(5y/6)=72

13y-(2*5y)=72

13y-10y=72

3y=72

y=24 people

Therefore:

x=(5*24)/6

x=20 people

Therefore people in the club before are 20+24=44

5 0
2 years ago
Y=-(x + 1) - 5<br> find domain and range
In-s [12.5K]
This is the answer ......

4 0
3 years ago
Test the claim that the proportion of people who own cats is significantly different than 80% at the 0.2 significance level. The
sattari [20]

Answer:

C. H0 : p = 0.8 H 1 : p ≠ 0.8

The test is:_____.

c. two-tailed

The test statistic is:______p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

The p-value is:_____. 0.09887

Based on this we:_____.

B. Reject the null hypothesis.

Step-by-step explanation:

We formulate null and alternative hypotheses as  proportion of people who own cats is significantly different than 80%.

H0 : p = 0.8 H 1 : p ≠ 0.8

The alternative hypothesis H1 is that the 80% of the  proportion is different and null hypothesis is , it is same.

For a two tailed test for significance level = 0.2 we have critical value  ± 1.28.

We have alpha equal to 0.2  for a two tailed test . We divided alpha with 2 to get the answer for a two tailed test. When divided by two it gives 0.1 and the corresponding value is ± 1.28

The test statistic is

p ± z (base alpha by 2) \sqrt{\frac{pq}{n} }

Where p = 0.8 , q = 1-p= 1-0.8= 0.2

n= 200

Putting the values

0.8 ± 1.28 \sqrt{\frac{0.8*0.2}{200} }

0.8 ± 0.03620

0.8362, 0.7638

As the calculated value of z lies within the critical region  we reject the null hypothesis.

8 0
3 years ago
A rectangular cereal box has a base of 189 square centimeters and a height of 32 centimeters what's the volume
ch4aika [34]
189×32=6048.....did it help???
6 0
3 years ago
Read 2 more answers
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