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3 years ago

Find x, the missing side length in the right triangle 18 8

Mathematics

2 answers:

Sergio [31]3 years ago

7 0

A^2 + B^2 = C^2
18^2 + 8^2 = 388
C = 20

Verizon [17]3 years ago

5 0

Answer:

19.7

Step-by-step explanation:

a^2+b^2=c^2

so 18^2+8^2=x^2

324+64=388

x is about 19.7

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The table showing the stock price changes for a sample of 12 companies on a day is contained in the Excel file below.

AfilCa [17]

Answer:

(a) The sample variance for the daily price change is 0.2501.

(b) The sample standard deviation for the daily price change is 0.5001.

Step-by-step explanation:

Let the random variable X denote the stock price changes for a sample of 12 companies on a day.

The data provided is:

X = {0.82 , 1.44 , -0.07 , 0.41 , 0.21 , 1.33 , 0.97 , 0.30 , 0.14 , 0.12 , 0.42 , 0.15}

(a)

The formula to compute the sample variance for the daily price change is:

$s^{2}=\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}$

The sample mean is computed using the formula:

$\bar X=\frac{1}{n}\sum\limits^{12}_{i=1}{X_{i}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample mean and sample variance are:

$\bar X$ =AVERAGE(A2:A13)

$s^{2}$ =VAR.S(A2:A13)

Thus, the sample variance for the daily price change is 0.2501.

(b)

The formula to compute the sample standard deviation for the daily price change is:

$s=\sqrt{\frac{1}{n-1}\sum\limits^{12}_{i=1}{(X_{i}-\bar X)^{2}}}$

Consider the Excel output attached below.

In Excel the formula to compute the sample standard deviation is:

$s$ =STDEV.S(A2:A13)

Thus, the sample standard deviation for the daily price change is 0.5001.

(c)

The (1 - α)% confidence interval for population variance is:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

Compute the critical value of Chi-square for α = 0.05 and (n - 1) = (12 - 1) = 11 degrees of freedom as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2,11}=21.920$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{(1-0.05/2),11}=\chi^{2}_{0.975,11}=3.816$

*Use a Chi-square table.

Compute the 95% confidence interval estimates of the population variance as follows:

$CI=[\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2} } \leq \sigma^{2}\leq \frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2} } ]$

$=[\frac{(12-1)\times 0.2501}{21.920 } \leq \sigma^{2}\leq \frac{(12-1)\times 0.2501}{3.816} ]$

$=[0.125506\leq \sigma^{2}\leq 0.720938]\\\approx [0.1255, 0.7210]$

Thus, the 95% confidence interval estimates of the population variance is (0.1255, 0.7210).

7 0

4 years ago

Eduardo thinks of a number between 1 and 20 that has exactly 5 factors.what number is he thinking of?

Brilliant_brown [7]

The answer would be 16

7 0

3 years ago

3. Sophia earns straight commission selling cell phone contracts. Last month she sold 341 cell phone contracts worth a total of

LUCKY_DIMON [66]

Answer:

28.2

Step-by-step explanation:

341-322.8

6 0

3 years ago

Given the probabilities for independent events A and

Mariana [72]

Answer:

P(A and B) = 0.2

Step-by-step explanation:

P(A and B) = P(A) * P(B) = 0.5 * 0.4 = 0.2

8 0

3 years ago

If a line passes through the point (0,-8), the y-intercept is

butalik [34]

Answer:

y-intercept = -8

Step-by-step explanation:

The y-intercept is where the line goes through the y axis. It is also the value when x = 0. From what the problem gives us, we know the y-intercept is -8 because the x value is 0

7 0

3 years ago