Answer: Un alambre de acero de 1.5 m se estira 2.0 mm con fuerza F. El diámetro del alambre de acero es 4.0 mm. El módulo de Young del acero es 2.0 x 1011 Nm-2. Determine la fuerza F aplicada sobre el alambre.
Step-by-step explanation:
Answer: 2500 grams
Step-by-step explanation: 2.5 x 1000 = 2500
Let the length equal x
Then the width would be 4x + 8 (8 feet more than 4 times the length)
Area = length x width:
5,472 = x * 4x+ 8
Simplify:
5472 = 4x^2 + 8x
Subtract 5472 from both sides:
4 x^2 + 8x - 5472 = 0
Use the quadratic formula to solve for x.
X = 36
Now you know the length is 36 feet
The width = 4(36) + 8 = 152 feet
Now find the perimeter: 152 + 152 + 36 + 36 = 376 feet.
The answer is B. 376
