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Feliz [49]
3 years ago
6

Elisa withdraw $20 at a time from her bank account and withdraw a total of $140. Ana withdrew $45 at a time from her bank accoun

t and withdrew a total of $270. Who made the greater number of withdrawals? Justify your answer?
Mathematics
2 answers:
ratelena [41]3 years ago
7 0
Hey there!

In order to find the number of withdrawals that Elisa and Ana drew from their bank accounts, just divide the total amount of money that was withdrawn by the amount that was withdrawn each time they visited the bank. 

Elisa: $140 ÷ $20 = 7 withdrawals 

Ana: $270 ÷ $45 = 6 withdrawals

As you can see, Elisa withdrew one more time than Ana did. Elisa will be your answer. You can justify this answer with the division we did to get this answer. 

Hope this helped you out! :-)
emmainna [20.7K]3 years ago
4 0
Elisa made a greater number because when you divide $140 by $20 you get 7. So that is seven Twenty dollar bills. For Ana, you divide $270 by $45 and you get 6. So for Ana you get 6 withdrawals of $45.
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Tina completed 2/3 of her homework. George completed 7/8 of his homework. Who completed a greater fraction of homework
Amiraneli [1.4K]

get a common denominator of 24

2/3 * 8/8  vs 7/8 * 3/3

16/24 vs 21/24

16/24<21/24

2/3 <7/8

George did more work

6 0
3 years ago
Which problem would you use the following proportion to solve for? = what is 40% of 24? what percent is 24 of 40? twenty-four is
ser-zykov [4K]
First you have to remember that to find a percentage you can multiply a number by the percentage's decimal form, for example 40% of 100 would be .40 * 100.
Anyways, 24*.40 =9.6.
To find the percentage however, you must divide 24/40 which equals 0.6, which is equal to the percentage 60%.
To find the third question, you must multiply 24 by 2.5 (0.4 * 2.5 = 1) and you should get 60.
The last question you may have made a typo on, you repeated the first question.
5 0
3 years ago
Read 2 more answers
The Answer to This Question
xenn [34]

Recall the Trigonometric Ratio below:

\tt{ \large{sin \theta =  \frac{opposite}{hypotenuse} } }\\   \tt{\large{cos \theta =  \frac{adjacent}{hypotenuse} }} \\    \tt{ \large{tan \theta =  \frac{opposite}{adjacent} }}

For csc, sec and cot - they are reciprocal of sin,cos and tan.

\tt{ \large{csc  \theta =  \frac{1}{sin \theta} } }\\  \tt{ \large{sec \theta =  \frac{1}{cos \theta} }} \\  \tt{ \large{cot \theta =  \frac{1}{tan \theta} }}

What we know now is our hypotenuse, adjacent and opposite length.

  • hypotenuse = 15
  • opposite = 12
  • adjacent = 9

Therefore,

\large{sin \theta =  \frac{12}{15}  \longrightarrow  \frac{4}{5} } \\ \large{cos \theta =  \frac{9}{15}   \longrightarrow  \frac{3}{5} } \\  \large{ tan \theta =  \frac{12}{9}  \longrightarrow  \frac{4}{3} }As for the reciprocal of three trigonometric ratio. We just swap the numerator and denominator.

\large{csc \theta =  \frac{15}{12}  \longrightarrow  \frac{5}{4} } \\  \large{sec \theta =  \frac{15}{9}  \longrightarrow  \frac{5}{3} }   \\  \large{cot \theta =   \frac{9}{12}  \longrightarrow \frac{3}{4} }

Answer

  • sin = 12/15 —> 4/5
  • cos = 9/15 —> 3/5
  • tan = 12/9 —> 4/3
  • csc = 15/12 —> 5/4
  • sec = 15/9 —> 5/3
  • cot = 9/12 —> 3/4

The first is non-simplifed form while the second that has the arrow pointing is the simplest form.

Let me know if you have any doubts.

5 0
3 years ago
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Please Help......If you were to flip a coin 60 times, how many times would you expect the coin to land on heads?
pentagon [3]

Answer:

30

Step-by-step explanation:

Again there are TWO sides so it would be 50% chance of getting head, or 50% of getting tail. So it would probably be 30

4 0
3 years ago
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-8 |5n| - 4 = -4<br><br> y and x
ale4655 [162]

n

- 8 |5n|  - 4 =  - 4

- 8 |5n| =  - 4 + 4

- 8 \times 5n = 0

- 40n = 0

- 40n \: over - 40 = 0 \: over - 40

n = 0

7 0
3 years ago
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