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liubo4ka [24]
3 years ago
6

Help anyone 8th grade math need it asap

Mathematics
2 answers:
andre [41]3 years ago
7 0
I have to have 20 characters but x is 22
krok68 [10]3 years ago
3 0

Answer:

22

Step-by-step explanation:

\frac{0.4x-2.8}{4} = 1.5\\

0.4x - 2.8 = 6

0.4x = 8.8

x = 22

\therefore the value of x is 22

Hope this helps :)

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What is the value of x when -25(x - 4) = -55(x - 10) ?
Free_Kalibri [48]

Simplify both sides of the equation

-25(x-4)=-55(x-10)

(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)

Distribute

-25x+100=-55x+550

Add 55x  to both sides

-25x+100+55x=-55x+550+55x

30x+100-100=550-100

subtract 100 from both sides

30x+100-100=550-100

30x=450

divide both sides by 30

30x/30=450/30

x= 15

The value of x is 15


I hope that's help you my friend !

5 0
3 years ago
Read 2 more answers
Which equation matches the graph
Alina [70]

Answer:

C

Step-by-step explanation:

You can see from the graph that everytime x goes up by 1, y goes down by 4, so the slope is -4.

The y-intercept is at -1

This means that the equation would be C. y = -4x - 1

8 0
3 years ago
In your computation, approximate its value as 3.14.
andrey2020 [161]

Answer: d

Step-by-step explanation:

Find the area of the rectangle.

A=l*w\\A=(15in)(12in)\\A=180in^2

Find the area of the base of the semicircle.

A=\pi r^2

12 in would be the diameter, divide by 2 to get the radius.

\frac{12}{2}=6

Plug this into the formula.

A=(3.14)(6)^2\\A=113.04in^2

Since we do not have a full circle but a semi one instead, we must divide our result by 2.

\frac{113.04}{2}=56.52in^2

Add both areas.

180+56.52=236.52in^2

7 0
3 years ago
Ticketd to the school play cost $11 for adults and $6 for children. What expression can be used to find the toyal cost for x adu
Makovka662 [10]

Answer:221

Step-by-step explanation:

4 0
4 years ago
Please help!!
oksano4ka [1.4K]
1. -6 ≤ x < -1 . . . . conjunction
2. x ≤ 6 . . or . . 10 ≤ x . . . . disjunction
3. 7 ≤ x < 12 . . . . conjunction
4. x < -9 . . or . . -3 ≤ x . . . . disjunction
5. 2 ≤ x ≤ 5 . . . . conjunction
6. x ≤ 54 . . or . . 66 ≤ x . . . . disjunction
7. 39 < x ≤ 43 . . . . conjunction

_____
Your problem statement provided no letters.
8 0
3 years ago
Read 2 more answers
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