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sesenic [268]
3 years ago
6

The circumference of a circular tabletop is 72ππ inches. What is the area, in square inches, of the tabletop?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
6 0
1] The circumference=72π, thus the radius will be found as follows:
C=2πr
therefore radius r will be:
2πr=72ππ
r=(72ππ)/(2π)
r=36
hence:
Area=πr²=π(36)²=1296π

2] Circumference= 32ππ, the radius will be:
C=2πr
2πr=32π
r=(32π)/2π
r=16

3] Radius of circle P is 24 cm, radius of circle Q is 8 cm:
Area of circle P is:
A=πr²=π×24²=576π
Area of circle Q is:
A=πr^2=π×8²=64π
therefore comparing the two areas:
(576π)/(64π)=9
Therefore we conclude that:
The area of circle P is 9 times the area of circle Q

4] Is incomplete

5] Circumference is 32π, the diameter will be:
C=πd
where d is the diameter, thus:
32π=πd
d=32
the answer is diameter is 32
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Answer:

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Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

LA=\pi rl

we have

LA=255\pi\ cm^{2}

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substitute the values

255\pi=\pi r(17)

Simplify

255=r(17)

r=255/(17)=15\ cm

step 2

Find the height of the cone

Applying the Pythagoras Theorem

l^{2} =r^{2} +h^{2}

substitute the values and solve for h

17^{2} =15^{2} +h^{2}

h^{2}=17^{2}-15^{2}

h^{2}=64

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step 3

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2}h

substitute the values

V=\frac{1}{3}\pi (15)^{2}(8)

V=600\pi\ cm^{3}

step 4

Find the specific weight

Divide the mass by the volume

\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}

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