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ExtremeBDS [4]
2 years ago
9

In ΔJKL, j = 93 cm, k = 82 cm and l=86 cm. Find the measure of ∠J to the nearest degree.

Mathematics
2 answers:
zhuklara [117]2 years ago
8 0

Answer:

5

Step-by-step explanation:

Answer:

85t

Step-by-step explanation:

1. Volume of a cone: 1. V = (1/3)πr2h 2. Slant height of a cone: 1. s = √(r2 + h2) 3. Lateral surface area of a cone: 1. L = πrs = πr√(r2 + h2) 4. Base surface area of a cone (a circle): 1. B = πr2 5. Total surface area of a cone: 1. A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))

hope this helps

tamaranim1 [39]2 years ago
7 0

Answer: 67 degrees

i don't know what this person is doing

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Answer: $14.0

Step-by-step explanation:

For us to calculate this question, we have to find 20% of $17.45 and then subtract the value gotten from $17.45. This will be:

= $17.45 - (20% × $17.45)

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Novay_Z [31]

Answer:

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Step-by-step explanation:

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Substitute ∠BEF= 4x:

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