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3 years ago

PLEASE HELP AND EXPLAIN

Mathematics

2 answers:

Flura [38]3 years ago

8 0

Gurll soryy your screwed

nadezda [96]3 years ago

5 0

I have never see this in my. Life

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Shkiper50 [21]

Answer:

Step-by-step explanation:

4 0

3 years ago

Can someone help me please? i'm not sure if 4 is right and i don't understand how to do 3

PtichkaEL [24]

3 Is B. The formula for finding the area of a circle is A= r(to the second power) times Pi. The radius is 6, so you must do 6 to the second power which is 6 times 6. That is 36. Your answer will be 36 pi.

3 0

3 years ago

Simplify (4x2+ 12x − 9) + (7x2− x + 3).

Leni [432]

Answer:
D ) 11 x² + 11 x - 6 .. .. ... ... ... .
. . . . . . . . .

7 0

4 years ago

Hudson and Katie are in a race and Hudson is running at 8-8 feet per sec. Katie gets 30 feet head start and is running in 6.3 fe

Sphinxa [80]

Answer:

12s.

Step-by-step explanation:

Given:

Hudson's velocity, Vh = 8.8 ft/s

Katie's velocity, Vk = 6.3 ft/s

Kate's head start distance, Dk = 30 ft

From the above, Katie and Hudson meet at th = tk = t

But, Dk = Dh + 30

Velocity = Distance/time

t × Vk = Dk

t × Vh = Dh

t × Vk + 30 = Dk

t × Vk + 30 = Vh × t

6.3t + 30 = 8.8t

t = 30/2.5

= 12 s

7 0

3 years ago

Maria drove from chicago, illinois, to milwaukee, wisconsin, a distance of 90 miles, at a mean speed of 56 miles per hour. on he

olya-2409 [2.1K]

- first trip: the distance is
S=90 m
while the speed is
v=56 m/h
Therefore the time taken is
$t_1= \frac{S}{v_1}= \frac{90 m}{56 m/h}= 1.6 h$

- second trip: the distance covered is still the same,
S=90 m
while the average speed this time was
v=49 m/h
Therefore, the time taken for the second trip was
$t_2 = \frac{S}{v_2}= \frac{90 m}{49 m/h}=1.8 h$

- The average speed for the whole trip is the total distance divided by the total time taken:
$v= \frac{S_1 + S_2 }{t_1+t_2}= \frac{90 m+90 m}{1.6 h+1.8 h}=52.9 m/h$

8 0

3 years ago