All categories

3 years ago

The triangle below can be best classified as?

Mathematics

1 answer:

Ierofanga [76]3 years ago

3 0

Answer:

obtuse scalene

Step-by-step explanation:

Three different sizes.

You might be interested in

Plzzzz help!!!!!!!!!!!!!

sertanlavr [38]

The answer to the question I believe is C

7 0

3 years ago

Read 2 more answers

The members of the boosters organization at your high school bought new balls for the school . They spent $ 22.00 per basketball

azamat

The askser is 283828288288 god it’s da key bro

6 0

3 years ago

Solve the system of equations:<br> y = 3x<br> y=x2-4

Lubov Fominskaja [6]

Answer:

x = -4

y = -12

Step-by-step explanation:

Since y is 3x,

3x = 2x - 4

On solving we get x as -4

Substitute x and we get y as -12

3 0

3 years ago

Read 2 more answers

A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p

Alekssandra [29.7K]

Using the z-distribution and the formula for the margin of error, it is found that:

a) A sample size of 54 is needed.

b) A sample size of 752 is needed.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

90% confidence level, hence $\alpha = 0.9$ , z is the value of Z that has a p-value of $\frac{1+0.9}{2} = 0.95$ , so $z = 1.645$ .

Item a:

The estimate is $\pi = 0.213 - 0.195 = 0.018$ .

The sample size is <u>n for which M = 0.03</u>, hence:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.018(0.982)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.018(0.982)}$

$\sqrt{n} = \frac{1.645\sqrt{0.018(0.982)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.018(0.982)}}{0.03}\right)^2$

$n = 53.1$

Rounding up, a sample size of 54 is needed.

Item b:

No prior estimate, hence $\pi = 0.05$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.03 = 1.645\sqrt{\frac{0.5(0.5)}{n}}$

$0.03\sqrt{n} = 1.645\sqrt{0.5(0.5)}$

$\sqrt{n} = \frac{1.645\sqrt{0.5(0.5)}}{0.03}$

$(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.5(0.5)}}{0.03}\right)^2$

$n = 751.7$

Rounding up, a sample of 752 should be taken.

A similar problem is given at brainly.com/question/25694087

5 0

3 years ago

A bake sale has 5 brownies for sale. Each brownie was cut into 4 slices. Each slice was sold for $7. What was the total amount e

Alona [7]

Answer:

the answer is $140

Step-by-step explanation:

5x4=20 20x7=140

4 0

3 years ago

Read 2 more answers