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nekit [7.7K]
2 years ago
13

Solve for all values of c in simplest form. |C – 21 |= 12

Mathematics
1 answer:
Rina8888 [55]2 years ago
5 0

Answer:

33, 9

Step-by-step explanation:

I33-21I=12

I9-21I=

I-12I=12

Every SUM of an absolute value will always be positive!!

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1. 60,30,90 right triangle. y will be hypotenuse/2, x will be
hypotenuse*sqrt(3)/2. So x = 16*sqrt(3)/2 = 8*sqrt(3), approximately 13.85640646 
y = 16/2 = 8  
2. 45,45,90 right triangle (2 legs are equal length and you have a right angle).
X and Y will be the same length and that will be hypotenuse * sqrt(2)/2. So 
x = y = 8*sqrt(2) * sqrt(2)/2 = 8*2/2 = 8 
 3. Just a right triangle with both legs of known length. Use the Pythagorean theorem 
x = sqrt(12^2 + 5^2) = sqrt(144 + 25) = sqrt(169) = 13  
4. Another right triangle with 1 leg and the hypotenuse known. Pythagorean theorem again. 
y = sqrt(1000^2 - 600^2) = sqrt(1000000 - 360000) = sqrt(640000) = 800  5. A 45,45,90 right triangle. One leg known. The other leg will have the same length as the known leg and the hypotenuse can be discovered with the Pythagorean theorem.  x = 6. y = sqrt(6^2 + 6^2) = sqrt(36+36) = sqrt(72) = sqrt(2 * 36) = 6*sqrt(2), approximately 8.485281374  
6. Another 45,45,90 triangle with the hypotenuse known. Both unknown legs will have the same length. And Pythagorean theorem will be helpful. 
x = y. 
12^2 = x^2 + y^2 
12^2 = x^2 + x^2 
12^2 = 2x^2 
144 = 2x^2 
72 = x^2 
sqrt(72) = x 
6*sqrt(2) = x 
x is approximately 8.485281374  
7. A 30,60,90 right triangle with the short leg known. The hypotenuse will be twice the length of the short leg and the remaining leg can be determined using the Pythagorean theorem. 
y = 11*2 = 22. 
x = sqrt(22^2 - 11^2) = sqrt(484 - 121) = sqrt(363) = sqrt(121 * 3) = 11*sqrt(3). Approximately 19.05255888  
8. A 30,60,90 right triangle with long leg known. Can either have fact that in that triangle, the legs have the ratio of 1:sqrt(3):2, or you can use the Pythagorean theorem. In this case, I'll use the 1:2 ratio between the unknown leg and the hypotenuse along with the Pythagorean theorem. 
x = 2y 
y^2 = x^2 - (22.5*sqrt(3))^2 
y^2 = (2y)^2 - (22.5*sqrt(3))^2 
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y = sqrt(2025/4) = sqrt(2025)/sqrt(4) = 45/2 
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10. Another right triangle, another use of the Pythagorean theorem. 
x = sqrt(50^2 - 14^2) = sqrt(2500 - 196) = sqrt(2304) = 48
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