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Ksivusya [100]
2 years ago
8

Hellllllllppppppppppppppppp

Mathematics
1 answer:
Likurg_2 [28]2 years ago
7 0

Answer:

1'

S45tep-by-step explanation:

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Last Monday, two law students met up at café Literatura after school to read the pages they were assigned in the legal methods c
jonny [76]

Answer:

N_{a} = T_{a}

N_{c} = 2 \times T_{c}

Step-by-step explanation:

Alejandro has read 28 pages so far and he can read 1 page per minute.

Again, Carly has read 12 pages so far and he can read 2 pages per minute.

If the variable N represents the number of pages read by the readers and T in minutes represents the time spent by the reader to read this number of pages, then  

For Alejandro: N_{a} = 1 \times T_{a} = T_{a} ......... (1)

For Carly: N_{c} = 2 \times T_{c} .......... (2)

So, the equations (1) and (2) gives the number of pages that Alejandro and Carly read. (Answer)

4 0
3 years ago
Ronnie wants to buy a computer table that measures 10 feet by 6 feet. The cost of the table is $16 per square feet. How much wil
irakobra [83]

Answer:  $960

Step-by-step explanation:

10*6= 60

60*16= 960

4 0
3 years ago
Work out 5 x 10^6 / 4 x 10^4<br> Give your answer as an ordinary number.
Angelina_Jolie [31]

Answer:

1.25 \times  {10}^{2} = 125

Step-by-step explanation:

\frac{5 \times  {10}^{6} }{4 \times  {10}^{4} }  =  \frac{5}{4}  \times  \frac{ {10}^{6} }{ {10}^{4} }  = 1.25 \times  {10}^{2} = 125

5 0
3 years ago
What are the values of the plots on the number lines?
Elina [12.6K]

Answer:

14. - 15

Step-by-step explanation:

The first one is located at 14. The second one is located at - 15

8 0
2 years ago
Find the intersection points using substitution or elimination for each system of equations:
natka813 [3]

Answer:

Step-by-step explanation:

Okay, so I think I know what the equations are, but I might have misinterpreted them because of the syntax- I think when you ask a question you can use the symbols tool to input it in a more clear way, otherwise you can use parentheses and such.

Problem 1:

(x²)/4 +y²= 1

y= x+1

*substitute for y*

Now we have a one-variable equation we can solve-

x²/4 + (x+1)² = 1

x²/4 + (x+1)(x+1)= 1

x²/4 + x²+2x+1= 1

*subtract 1 from both sides to set equal to 0*

x²/4 +x^2+2x=0

x²/4 can also be 1/4 * x²

1/4 * x² +1*x² +2x = 0

*combine like terms*

5/4 * x^2+2x+ 0 =0

now, you can use the quadratic equation to solve for x

a= 5/4

b= 2

c=0

the syntax on this will be rough, but I'll do my best...

x= (-b ± √(b²-4ac))/(2a)

x= (-2 ±√(2²-4*(5/4)*(0))/(2*(5/4))

x= (-2 ±√(4-0))/(2.5)

x= (-2±2)/2.5

x will have 2 answers because of ±

x= 0 or x= 1.6

now plug that back into one of the equations and solve.

y= 0+1 = 1

y= 1.6+1= 2.6

Hopefully this explanation was enough to help you solve problem 2.

Problem 2:

x² + y² -16y +39= 0

y²- x² -9= 0

6 0
3 years ago
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