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dsp73
2 years ago
6

Louise, Tammy, Delores, and Sheryl score 78 points total in the tennis matches they play. They score a consecutive number of poi

nts from smallest to greatest in respect to the order of the names mentioned. How many points does Louise score?
Mathematics
1 answer:
irga5000 [103]2 years ago
5 0

\huge\boxed{18\ \text{points}}

We'll represent Louise's, Tammy's, Delores's, and Sheryl's point values with x, x+1, x+2, and x+3 respectively since each one is 1 point more than the last.

Add all of these values up and set it all equal to 78.

x+x+1+x+2+x+3=78

Now, simplify.

4x+6=78

Subtract 6 on both sides.

\begin{aligned}4x+6-6&=78-6\\4x&=72\end{aligned}

Divide both sides by 4.

\begin{aligned}\frac{4x}{4}&=\frac{72}{4}\\x&=\boxed{18}\end{aligned}

Since Louise's score is x, the answer is 18.

<h3>Double-checking</h3>

To verify our answer, add the point totals 18, 19, 20, and 21.

This equals 78, so we can be sure the answer is correct.

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federico ha tomado 2/5 de vaso de leche y maria ,4/10de vaso ¿alguno de los dos ha bebido mas leche o han bebido la misma cantid
umka2103 [35]

Answer:

Han bebido la misma cantidad.

Step-by-step explanation:

De la pregunta,

Frederico = 2/5 vaso de leche

María = 4/10 vaso de leche

Simplificando el gozo de la leche para María

= 2/5

Por tanto, podemos decir que:

Sí, han bebido la misma cantidad.

5 0
3 years ago
Solve for x 3x+3/x-4 = 3x+2/x+4
Lerok [7]

Answer:

here you go! with step by step so you can do it next time

5 0
3 years ago
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Can sum1 pls help? lol ty
cupoosta [38]

Answer:

C?

Step-by-step explanation:

5 0
3 years ago
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Find the critical points of the function f(x, y) = 8y2x − 8yx2 + 9xy. Determine whether they are local minima, local maxima, or
NARA [144]

Answer:

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

Step-by-step explanation:

The function is:

f(x,y) = 8\cdot y^{2}\cdot x -8\cdot y\cdot x^{2} + 9\cdot x \cdot y

The partial derivatives of the function are included below:

\frac{\partial f}{\partial x} = 8\cdot y^{2}-16\cdot y\cdot x+9\cdot y

\frac{\partial f}{\partial x} = y \cdot (8\cdot y -16\cdot x + 9)

\frac{\partial f}{\partial y} = 16\cdot y \cdot x - 8 \cdot x^{2} + 9\cdot x

\frac{\partial f}{\partial y} = x \cdot (16\cdot y - 8\cdot x + 9)

Local minima, local maxima and saddle points are determined by equalizing  both partial derivatives to zero.

y \cdot (8\cdot y -16\cdot x + 9) = 0

x \cdot (16\cdot y - 8\cdot x + 9) = 0

It is quite evident that one point is (0,0). Another point is found by solving the following system of linear equations:

\left \{ {{-16\cdot x + 8\cdot y=-9} \atop {-8\cdot x + 16\cdot y=-9}} \right.

The solution of the system is (3/8, -3/8).

Let assume that y = 0, the nonlinear system is reduced to a sole expression:

x\cdot (-8\cdot x + 9) = 0

Another solution is (9/8,0).

Now, let consider that x = 0, the nonlinear system is now reduced to this:

y\cdot (8\cdot y+9) = 0

Another solution is (0, -9/8).

The next step is to determine whether point is a local maximum, a local minimum or a saddle point. The second derivative test:

H = \frac{\partial^{2} f}{\partial x^{2}} \cdot \frac{\partial^{2} f}{\partial y^{2}} - \frac{\partial^{2} f}{\partial x \partial y}

The second derivatives of the function are:

\frac{\partial^{2} f}{\partial x^{2}} = 0

\frac{\partial^{2} f}{\partial y^{2}} = 0

\frac{\partial^{2} f}{\partial x \partial y} = 16\cdot y -16\cdot x + 9

Then, the expression is simplified to this and each point is tested:

H = -16\cdot y +16\cdot x -9

S1: (0,0)

H = -9 (Saddle Point)

S2: (3/8,-3/8)

H = 3 (Local maximum or minimum)

S3: (9/8, 0)

H = 9 (Local maximum or minimum)

S4: (0, - 9/8)

H = 9 (Local maximum or minimum)

Unfortunately, the second derivative test associated with the function does offer an effective method to distinguish between local maximum and local minimums. A more direct approach is used to make a fair classification:

S2: (3/8,-3/8)

f(\frac{3}{8} ,-\frac{3}{8} ) = - \frac{27}{64} (Local minimum)

S3: (9/8, 0)

f(\frac{9}{8},0) = 0 (Local maximum)

S4: (0, - 9/8)

f(0,-\frac{9}{8} ) = 0 (Local maximum)

Saddle point: (0,0)

Local minimum: (\frac{3}{8}, -\frac{3}{8})

Local maxima: (0,-\frac{9}{8}), (\frac{9}{8},0)

4 0
3 years ago
You usually buy a 16.5-ounce bottle of shampoo. There is a new bottle that says it gives you 30% more free.
Katarina [22]

Answer:

\frac{x-16.5}{16.5}=0.30

Hopefully, this is your desired setup. (I noticed the formula you have to fill in there.)

Have a good day.

Step-by-step explanation:

Hi.

You could use the percent change formula.

Since we know it is a percent increase then we will do new-old instead of old-new:

\frac{\text{new}-\text{old}}{\old}

x is the new amount of shampoo.

16.5 is the original amount (old) of shampoo.

The percent increase is 30%=0.30 .

So we have the following equation:

\frac{x-16.5}{16.5}=0.30

We could have found the equation like this:

16.5+16.5(0.30)=x

Subtract 16.5 on both sides:

16.5(0.30)=x-16.5

Divide both sides by 16.5:

0.30=\frac{x-16.5}{16.5}

By us of symmetric property of equality:

\frac{x-16.5}{16.5}=0.30

5 0
3 years ago
Read 2 more answers
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