The distance traveled, d = 2/5 miles = 0.4 miles.
The time taken to travel 0.4miles is given as, t = 1/4 hr = 0.25 hr.
Thus, the average speed, s = distance traveled divided by time taken.
i.e.

we can now go through the options and see the correct answers:
option A is correct because unit rate per hour is the same thing as average speed
option B is wrong because average speed is greater than 1mile/hr from our calculation above
option C is wrong because 13/5 gives us 2.6 miles/hr
option D is correct because the average speed is indeed greater than 1
option E is wrong because average speed is 1.6 miles/hr not 2 1/4 miles/hr
Thus, the answers are:
Option A and Option D