Please help deternmin id this is a function
2 answers:
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Answer:
0.3 or 30%
Step-by-step explanation:
Since no innocent student will ever be caught, the probability that a student sends an email and/or text message during a lecture AND gets caught is given by the product of the probability of a student sending a message (60%) by the probability of the professor catching them (50%) :
The probability is 0.3 or 30%.
Extraemos los datos del problema:
- Capital Inicial → C₀ = S/.25000
- Interés bimestral → i = 8 % = 0.08
- Periodos → n = 3
Capital Inicial Bimestre → C = S/.25000
Tasa de interés bimestral:
I = C×i
I = S/.25000 × 0.08
I = S/.2000
Monto final:
M = C + I
M = S/.25000 + S/.2000
M = S/.27000
Variación Porcentual:
% = (M - C₀) / C₀
% = ( 27000 - 25000) / 25000
% = 8
<h2>Bimestre 2:</h2>Capital Inicial Bimestre → C = S/.27000
Tasa de interés bimestral:
I = C×i
I = S/.27000 × 0.08
I = S/.2160
Monto final:
M = C + I
M = S/.27000 + S/.2160
M = S/.29160
Variación Porcentual:
% = (M - C₀) / C₀
% = ( 29160 - 25000) / 25000
% = 16.64
<h2>Bimestre 3:</h2>Capital Inicial Bimestre → C = S/.29160
Tasa de interés bimestral:
I = C×i
I = S/.29160 × 0.08
I = S/.2332.8
Monto final:
M = C + I
M = S/.29160 + S/.2332.8
M = S/ 31492.8
Variación Porcentual:
% = (M - C₀) / C₀
% = ( 31492.8 - 25000) / 25000
% = 25.97
We can assume that the y-intercept for this equation is 125, because that would be how much Anna already has saved before she begins saving money from her allowance. Then, we know that Anna adds $2 to her savings each day from the problem, so we know that the slope will be positive 2 then.
Equation:
y = 2x + 125
Graph:
Attached below
Hope this helps!! :)
